Sql server 仅限TSQL datediff营业时间
在视图中,这两个日期来自一个表:Sql server 仅限TSQL datediff营业时间,sql-server,tsql,time,datediff,Sql Server,Tsql,Time,Datediff,在视图中,这两个日期来自一个表: 2014-12-17 14:01:03.523 - 2014-12-20 09:59:28.783 我需要知道以小时为单位的日期差异,假设一天中我可以从上午8点到下午5点计算时间 当然,星期六和星期日不能包括在内 我尝试在select中使用此代码,但我只得到了天数的差异,不包括周六和周日 (DATEDIFF(HOUR, convert(datetime,t.EXT_DATAINS-2), convert(datetime,b.EXT_DATAINS-2)) +
2014-12-17 14:01:03.523 - 2014-12-20 09:59:28.783
我需要知道以小时为单位的日期差异,假设一天中我可以从上午8点到下午5点计算时间
当然,星期六和星期日不能包括在内
我尝试在select中使用此代码,但我只得到了天数的差异,不包括周六和周日
(DATEDIFF(HOUR, convert(datetime,t.EXT_DATAINS-2), convert(datetime,b.EXT_DATAINS-2)) + 1)
-(DATEDIFF(wk, convert(datetime,t.EXT_DATAINS-2), convert(datetime,b.EXT_DATAINS-2)) * 2)
-(CASE WHEN DATENAME(dw, convert(datetime,t.EXT_DATAINS-2)) = 'Sunday' THEN 1 ELSE 0 END)
-(CASE WHEN DATENAME(dw, convert(datetime,b.EXT_DATAINS-2)) = 'Saturday' THEN 1 ELSE 0 END) differenza
例如:
2014-12-17 : 3hrs
2014-12-18 : 8hrs
2014-12-19 : 8hrs
2014-12-20 : 2hrs
Tot : 21hrs
使用递归CTE获取带有日期的所有小时数
方法1:获取FromDate和ToDate之间小时数的所有日期
方法2:获取FromDate和ToDate之间缺少的日期,其中8硬编码为Hrs
此方法将更易于实现-性能优化
DECLARE @FROMDATE DATETIME='2014-12-17 14:01:03.523'
DECLARE @TODATE DATETIME='2014-12-20 09:59:28.783'
;WITH CTE AS
(
-- Get missing dates between FromDate and ToDate
SELECT DATEADD(DAY,1,@FROMDATE) FROMDATE,8 HRS
UNION ALL
SELECT DATEADD(DAY,1,FROMDATE),8
FROM CTE
WHERE FROMDATE < DATEADD(DAY,-1,@TODATE)
)
,CTE2 AS
(
-- Gets the Hours for FromDate
SELECT CAST(@FROMDATE AS DATE) DATES, CAST(CAST(DATEDIFF
(
MINUTE,@FROMDATE,CAST(CAST(CAST(@FROMDATE AS DATE) AS VARCHAR(12))+' 17:00:00' AS DATETIME)
)AS NUMERIC(18,2))/60 AS DECIMAL(18,0)) HRS
WHERE DATENAME(DW,@FROMDATE)<>'SATURDAY' AND DATENAME(DW,@FROMDATE)<>'SUNDAY'
UNION ALL
-- Select Hours in between dates
SELECT CAST(FROMDATE AS DATE) NEWDATE,HRS
FROM CTE
WHERE DATENAME(DW,FROMDATE)<>'SATURDAY' AND DATENAME(DW,FROMDATE)<>'SUNDAY'
UNION ALL
-- Select Hours for ToDate
SELECT CAST(@TODATE AS DATE), CAST(CAST(DATEDIFF
(
MINUTE,CAST(CAST(CAST(@TODATE AS DATE) AS VARCHAR(12))+' 08:00:00' AS DATETIME),@TODATE
)AS NUMERIC(18,2))/60 AS DECIMAL(18,0))
WHERE DATENAME(DW,@TODATE)<>'SATURDAY' AND DATENAME(DW,@TODATE)<>'SUNDAY'
)
-- Use ROLLUP to find the sum of Hours and show it in last row
SELECT ISNULL(CAST(DATES AS VARCHAR(20)),'Tot')DATES,
CAST(SUM(HRS)AS VARCHAR(4))+'hrs' HRS
FROM CTE2
GROUP BY DATES
WITH ROLLUP
@马可·伯罗梅托
创建一个静态表,该表将具有所有日历功能,如假日功能,周六和周日是假日。这将对您有很大帮助。可能与的重复没有标准功能可帮助您完成此操作。除了确定你的工作时间,午餐时间也算吗?在假日计划中,您必须定义范围在营业时间以外开始或结束时会发生什么。例如:如果从下午3点到6点,这是多少小时?上午3点到晚上10点怎么样?你想从这两个日期的差异中得到什么?你能告诉我们你试过什么吗,例如,用于从开始日期到结束日期运行的CTE或数字表,以及用于确定每个日期的小时数和最终结果的总和的案例?这两个日期2014-12-17 14:01:03.523-2014-12-20 09:59:28.783的差异是什么
DECLARE @FROMDATE DATETIME='2014-12-17 14:01:03.523'
DECLARE @TODATE DATETIME='2014-12-20 09:59:28.783'
;WITH CTE AS
(
-- Get missing dates between FromDate and ToDate
SELECT DATEADD(DAY,1,@FROMDATE) FROMDATE,8 HRS
UNION ALL
SELECT DATEADD(DAY,1,FROMDATE),8
FROM CTE
WHERE FROMDATE < DATEADD(DAY,-1,@TODATE)
)
,CTE2 AS
(
-- Gets the Hours for FromDate
SELECT CAST(@FROMDATE AS DATE) DATES, CAST(CAST(DATEDIFF
(
MINUTE,@FROMDATE,CAST(CAST(CAST(@FROMDATE AS DATE) AS VARCHAR(12))+' 17:00:00' AS DATETIME)
)AS NUMERIC(18,2))/60 AS DECIMAL(18,0)) HRS
WHERE DATENAME(DW,@FROMDATE)<>'SATURDAY' AND DATENAME(DW,@FROMDATE)<>'SUNDAY'
UNION ALL
-- Select Hours in between dates
SELECT CAST(FROMDATE AS DATE) NEWDATE,HRS
FROM CTE
WHERE DATENAME(DW,FROMDATE)<>'SATURDAY' AND DATENAME(DW,FROMDATE)<>'SUNDAY'
UNION ALL
-- Select Hours for ToDate
SELECT CAST(@TODATE AS DATE), CAST(CAST(DATEDIFF
(
MINUTE,CAST(CAST(CAST(@TODATE AS DATE) AS VARCHAR(12))+' 08:00:00' AS DATETIME),@TODATE
)AS NUMERIC(18,2))/60 AS DECIMAL(18,0))
WHERE DATENAME(DW,@TODATE)<>'SATURDAY' AND DATENAME(DW,@TODATE)<>'SUNDAY'
)
-- Use ROLLUP to find the sum of Hours and show it in last row
SELECT ISNULL(CAST(DATES AS VARCHAR(20)),'Tot')DATES,
CAST(SUM(HRS)AS VARCHAR(4))+'hrs' HRS
FROM CTE2
GROUP BY DATES
WITH ROLLUP