Sql server 选择DISTINCT issue，选择多个预订

我有两个表

tblReservation

和

tblBooking

。

tblReservation

有一个

ID

列和一个事件名称列

tblBooking

有自己的

ID

列，也有Reservation ID列（外键），然后是EventStart和EventEnd列

基本上，我正在做以下工作：

SELECT DISTINCT 
    B1.ReservationID,
    B1.EventStart,
    B1.EventEnd,
    tblReservation.EventName
FROM        
    tblBooking AS B1 
INNER JOIN
    tblReservation ON B1.ReservationID = tblReservation.ID
WHERE       
    B1.EventEnd = (SELECT MAX(B2.EventEnd)
                   FROM tblBooking AS B2
                   WHERE B2.ReservationID = B1.ReservationID)

我尝试了这个子查询，每次预订只提取一个预订ID。基本上我想要这些结果：

Reservation ID     EventStart    EventEnd     EventName
1                  1/1/18        1/2/18       Event 1
2                  1/2/18        1/3/18       Event 2 
3                  1/4/18        1/6/18       Event 3

相反，我得到的是：

Reservation ID     EventStart    EventEnd     EventName
1                  1/1/18        1/1/18       Event 1
1                  1/2/18        1/2/18       Event 1
2                  1/2/18        1/2/18       Event 2
2                  1/3/18        1/3/18       Event 2 

---

你能为你的预期结果提供一些样本数据吗？这非常有效，谢谢。我曾想过使用CTE，但是没有考虑过Rover号（分区…）请为您的代码提供一些解释。只有代码的答案很少对任何人有用，通常会被删除。

WITH X AS (
SELECT      
       B1.ReservationID
     , B1.EventStart
     , B1.EventEnd
     , tblReservation.EventName
     , ROW_NUMBER() OVER (PARTITION BY B1.ReservationID ORDER BY B1.[EventEnd] DESC) rn
FROM        tblBooking AS B1 
INNER JOIN  tblReservation ON B1.ReservationID = tblReservation.ID
)
SELECT 
       x.ReservationID
     , x.EventStart
     , x.EventEnd
     , x.EventName
FROM X 
WHERE x.rn = 1

select DISTINCT(B1.ReservationID), MIN(B1.EventStart) as EventStart, MAX(B1.EventEnd) as EventEnd, Res.EventName
from tblBooking B1
left join tblReservation Res on Res.ID = B1.ReservationID
GROUP BY B1.ReservationID, Res.EventName