根据sql中的月份和年份选择一行

我有一张这样的桌子：

 ID |     Cost     | Month |  Year  | InMonth | InYear |
--------------------------------------------------------
1081|     13000    |   5   |  2017  |    10   |  2016  |
1081|     13500    |   9   |  2016  |    10   |  2016  |
1081|     21000    |   2   |  2016  |    10   |  2016  |
1229|      6500    |   7   |  2017  |    10   |  2016  |
1229|      7800    |   5   |  2016  |    10   |  2016  |
1312|    110000    |   8   |  2017  |    10   |  2016  |
1312|    120000    |   5   |  2017  |    10   |  2016  |
1312|     99000    |   5   |  2016  |    10   |  2016  |

我想根据InMonth=Month和InYear=Year显示结果数据/行。如果InMonth与Month不相同，InYear与Year不相同，则获取以前的数据/行。像这样：

 ID |     Cost     | Month |  Year  | InMonth | InYear |
1081|     13500    |   9   |  2016  |    10   |  2016  |
1229|      7800    |   5   |  2016  |    10   |  2016  |
1312|     99000    |   5   |  2016  |    10   |  2016  |

我试过这个：

select "ID", "Cost", "Month", "Year"
 from ( select "ID", "Cost", "Month", "Year",
  case when "InMonth">="Month" and "InYear">="Year"
   then row_number() over(partition by "ID" order by "Year" desc, "Month" desc)
  else 0
 end as RN
from price_history
) X
where RN<>0

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SQL FIDLE:

您正在使用Postgres。我建议：

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您正在使用Postgres。我建议：

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对不起，我可以发邮件。我使用以下代码：

select "ID", "Cost", "Month", "Year", "rn"
 from ( select "ID", "Cost", "Month", "Year",
  row_number() over(partition by "ID" order by "Year" desc, "Month" desc)
  as RN
from price_history where "InMonth">="Month" and "InYear">="Year" 
) X
where RN=1

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对不起，我可以发邮件。我使用以下代码：

select "ID", "Cost", "Month", "Year", "rn"
 from ( select "ID", "Cost", "Month", "Year",
  row_number() over(partition by "ID" order by "Year" desc, "Month" desc)
  as RN
from price_history where "InMonth">="Month" and "InYear">="Year" 
) X
where RN=1

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将InMonth>=月和InYear>=年移到where子句不是更好吗。。你甚至不需要行号，那么为什么9出现在你的必选结果中而2不出现呢？谢谢大家，我已经解决了这个问题，将InMonth>=Month和InYear>=Year移到where子句不是更好吗。。你甚至不需要行号，那么为什么9出现在你的必选结果中而2不出现？谢谢大家，我已经解决了这个问题谢谢，我会在下一个问题中尝试谢谢，我会在下一个问题中尝试