sqlserver2000中的秩查询
我正在尝试创建一个查询,该查询将显示作业ID的最后状态。在SQL Server 2008中,使用“按分区排序”函数很简单,但在SQL Server 2000中,此函数不可用。 我在临时表job_history中通过job_ID升序和DATETIME descening将job_history按顺序排列-注意,pk_ID是在临时表中使用:IDENTITYint,1,1生成的,但这是我遇到的问题,我不知道如何对该表中的记录进行排序sqlserver2000中的秩查询,sql,sql-server,database,sql-server-2000,ranking,Sql,Sql Server,Database,Sql Server 2000,Ranking,我正在尝试创建一个查询,该查询将显示作业ID的最后状态。在SQL Server 2008中,使用“按分区排序”函数很简单,但在SQL Server 2000中,此函数不可用。 我在临时表job_history中通过job_ID升序和DATETIME descening将job_history按顺序排列-注意,pk_ID是在临时表中使用:IDENTITYint,1,1生成的,但这是我遇到的问题,我不知道如何对该表中的记录进行排序 SELECT h1.pk_ID, h1.Job_ID,
SELECT
h1.pk_ID,
h1.Job_ID,
h1.Status,
h1.DATETIME
FROM #JOB_HISTORY h1
ORDER BY h1.pk_ID ASC;
作业历史记录结果:
期望输出:
SQL Server可以自由地按照它想要的顺序插入记录,所以我不相信Identitynt,1,1总能为您提供正确的顺序。不过,它在某些版本中可能会起作用 您可以内部连接一个子查询,从中获取最大日期时间或最小主键ID以获取第一行/最后一行。下面是获取SQL Server 2000中每个作业的最后结果的工作示例:
use msdb;
select
sysjobhistory.job_id as job_id
-- https://msdn.microsoft.com/en-us/library/ms174997.aspx
, case sysjobhistory.run_status
when 0 then 'Failed'
when 1 then 'Succeeded'
when 2 then 'Retry'
when 3 then 'Canceled'
else cast(sysjobhistory.run_status as varchar(10))
end as run_status
, jobLastHistory.lastDateTime as execution_time
FROM dbo.sysjobhistory as sysjobhistory
inner join (
--last datetime for each job_id
SELECT
history.job_id
, max( --newest
CONVERT(DATETIME, STUFF(STUFF(STUFF( --yyyymmddhhmiss --> datetime
cast(history.run_date as varchar(8))--yyyymmdd
+right('000000'+cast(history.run_time as varchar(8)),6) --hhmiss
,13,0,':'),11,0,':'),9,0,' '))
) AS lastDateTime
FROM dbo.sysjobhistory as history
where history.step_id = 0 --job outcome
group by
history.job_id
) as jobLastHistory
on jobLastHistory.job_id
= sysjobhistory.job_id --same job
and convert(varchar(8),jobLastHistory.lastDateTime,112)
= sysjobhistory.run_date --latest date (yyyymmdd)
and replace(convert(varchar(8),jobLastHistory.lastDateTime,108),':','')
= sysjobhistory.run_time --latest time (hhmiss)
where sysjobhistory.step_id = 0 --job outcome
;
您可以通过自连接来实现这一点,但它确实很糟糕,而且效率极低,随着表的增大,成本/持续时间呈指数级增长。像2000这样一个残废的、不受支持的版本,你还要运行多久?我们没有升级的预算。使用SQL Server的前端程序不支持较新的SQL Server技术:我尝试了这个查询,但它不起作用,您将如何进行选择?选择h1.pk_ID,h1.Job_ID,h1.STATUS,h1.DATETIME FROM Job_hyst h1,Job_hyst h2,其中h2.DATETIME
Job_ID STATUS DATETIME
1234 Succeded. 2015-03-30 12:10
5678 Failed. 2015-04-02 04:00
use msdb;
select
sysjobhistory.job_id as job_id
-- https://msdn.microsoft.com/en-us/library/ms174997.aspx
, case sysjobhistory.run_status
when 0 then 'Failed'
when 1 then 'Succeeded'
when 2 then 'Retry'
when 3 then 'Canceled'
else cast(sysjobhistory.run_status as varchar(10))
end as run_status
, jobLastHistory.lastDateTime as execution_time
FROM dbo.sysjobhistory as sysjobhistory
inner join (
--last datetime for each job_id
SELECT
history.job_id
, max( --newest
CONVERT(DATETIME, STUFF(STUFF(STUFF( --yyyymmddhhmiss --> datetime
cast(history.run_date as varchar(8))--yyyymmdd
+right('000000'+cast(history.run_time as varchar(8)),6) --hhmiss
,13,0,':'),11,0,':'),9,0,' '))
) AS lastDateTime
FROM dbo.sysjobhistory as history
where history.step_id = 0 --job outcome
group by
history.job_id
) as jobLastHistory
on jobLastHistory.job_id
= sysjobhistory.job_id --same job
and convert(varchar(8),jobLastHistory.lastDateTime,112)
= sysjobhistory.run_date --latest date (yyyymmdd)
and replace(convert(varchar(8),jobLastHistory.lastDateTime,108),':','')
= sysjobhistory.run_time --latest time (hhmiss)
where sysjobhistory.step_id = 0 --job outcome
;