Sql 在每个句子前打印项目符号+；每句话后换行

我有一段文字，比如：第一句。第二句。第三句

我希望它是：

• 第一句
• 第二句
• 第三句

我想我可以用

'.

替换

'.+char（10）+char（13）

，但我如何才能处理项目符号呢？“•”如果手动打印，字符效果很好。我只是不知道如何在每个句子（包括第一句）中加上项目符号

-- Initial string
declare @text varchar(100)
set @text = 'Sentence one. Sentence two. Sentence three.'

-- Setting up replacement text - new lines (assuming this works) and bullets ( char(149) )
declare @replacement varchar(100)
set @replacement = '.' + char(10) + char(13) + char(149)

-- Adding a bullet at the beginning and doing the replacement, but this will also add a trailing bullet
declare @processedText varchar(100)
set @processedText = char(149) + ' ' + replace(@text, '.', @replacement)

-- Figure out length of substring to select in the next step
declare @substringLength int
set @substringLength = LEN(@processedText) - CHARINDEX(char(149), REVERSE(@processedText))

-- Removes trailing bullet
select substring(@processedText, 0, @substringLength)

我在这里测试过-

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我应该指出，在T-SQL中这样做似乎不正确。T-SQL用于处理数据；任何特定于演示文稿的工作都应该在调用此T-SQL（C#或您正在使用的任何东西）的代码中完成。

这是我的一种高高在上的方法，但我觉得这是一种相当可靠的方法。它结合了用于字符串切分的数字表的经典SQL问题解决技术和用于XML的

将拆分的行重新连接在一起。代码很长，但唯一需要实际编辑的地方是

SOURCE\u DATA

部分

没有对@Jeremy Wiggins方法的攻击，但我更喜欢我的方法，因为它比基于集合的方法更适合，而且代码效率也相当高

-- This code will rip lines apart based on @delimiter
-- and put them back together based on @rebind
DECLARE 
    @delimiter char(1)
,   @rebind varchar(10);

SELECT
    @delimiter = '.'
,   @rebind = char(10) + char(149) + ' ';

;
-- L0 to L5 simulate a numbers table
-- http://billfellows.blogspot.com/2009/11/fast-number-generator.html
WITH L0 AS
(
    SELECT
        0 AS C
    UNION ALL
    SELECT
        0
)
, L1 AS
(
    SELECT
        0 AS c
    FROM
        L0 AS A
        CROSS JOIN L0 AS B
)
, L2 AS
(
    SELECT
        0 AS c
    FROM
        L1 AS A
        CROSS JOIN L1 AS B
)
, L3 AS
(
    SELECT
        0 AS c
    FROM
        L2 AS A
        CROSS JOIN L2 AS B
)
, L4 AS
(
    SELECT
        0 AS c
    FROM
        L3 AS A
        CROSS JOIN L3 AS B
)
, L5 AS
(
    SELECT
        0 AS c
    FROM
        L4 AS A
        CROSS JOIN L4 AS B
)
, NUMS AS
(
    SELECT
        ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) AS number
    FROM
        L5
)
, SOURCE_DATA (ID, content) AS
(
    -- This query simulates your input data
    SELECT 1, 'Sentence one. Sentence two. Sentence three.'
    UNION ALL SELECT 7, 'In seed time learn, in harvest teach, in winter enjoy.Drive your cart and your plow over the bones of the dead.The road of excess leads to the palace of wisdom.Prudence is a rich, ugly old maid courted by Incapacity.He who desires but acts not, breeds pestilence.'
)
, MAX_LENGTH AS
(
    -- this query is rather important. The current NUMS query generates a 
    -- very large set of numbers but we only need 1 to maximum lenth of our
    -- source data. We can take advantage of a 2008 feature of letting
    -- TOP take a dynamic value
    SELECT TOP (SELECT MAX(LEN(SD.content)) AS max_length FROM SOURCE_DATA SD)
        N.number
    FROM
        NUMS N
)
, MULTI_LINES AS
(
    -- This query will make many lines out a single line based on the supplied delimiter
    -- Need to retain the ID (or some unique value from original data to regroup it
    -- http://www.sommarskog.se/arrays-in-sql-2005.html#tblnum
    SELECT 
        SD.ID
    ,   LTRIM(substring(SD.content, Number, charindex(@delimiter, SD.content + @delimiter, Number) - Number)) + @delimiter AS lines
    FROM
        MAX_LENGTH
        CROSS APPLY
            SOURCE_DATA SD
    WHERE
        Number <= len(SD.content)
        AND substring(@delimiter + SD.content, Number, 1) = @delimiter
)
, RECONSITITUE (content, ID) AS
(
    -- use classic concatenation to put it all back together
    -- using CR/LF * (space) as delimiter
    -- as a correlated sub query and joined back to our original table to preserve IDs
    -- https://stackoverflow.com/questions/5196371/sql-query-concatenating-results-into-one-string
    SELECT DISTINCT 
    STUFF
    ( 
        (
            SELECT @rebind + M.lines
            FROM MULTI_LINES M
            WHERE M.ID = ML.ID
            FOR XML PATH('')
        )
    , 1
    , 1
    , '')
    ,   ML.ID
    FROM 
        MULTI_LINES ML
)
SELECT 
    R.content
,   R.ID
FROM 
    RECONSITITUE R

工具书类

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在SSMS中，当您将结果发送到网格（默认输出）时，换行符没有任何效果。如果将结果发送到文本（ctrl-T），则可以看到正确显示的换行符。我唯一要指出的是，在第2/3行的子弹之间有一个空格，但在第1行的子弹之间没有。哦，酷，我不知道。空间也很好。查询和链接已适当更新，泰。对提交的答案有任何反馈吗？这些对你有用吗？很抱歉反应太晚了。我从来没有机会测试这个东西，但现在我做了，它就像一个符咒！另外，谢谢你的链接。信息量很大。

content                                                       ID
-----------------------------------------------------------   ---
• In seed time learn, in harvest teach, in winter enjoy.
• Drive your cart and your plow over the bones of the dead.
• The road of excess leads to the palace of wisdom.
• Prudence is a rich, ugly old maid courted by Incapacity.
• He who desires but acts not, breeds pestilence.             7
• Sentence one.
• Sentence two.
• Sentence three.                                             1

(2 row(s) affected)