如何透视tsql中的第二列

以下是我当前的数据集：

rname   ename
Advises Grad_student
Advises Faculty
Chairs  Department
Chairs  Faculty

我正在尝试将其转换为以下格式：

rname    ename1        ename2
advises  grad_student  faculty
chairs   department    faculty

以下是我迄今为止所尝试的：

select distinct 
r1.rname, r1.ENAME as ename1,r2.ENAME as ename2
from [dbo].[RELATIONSHIPS] r1
inner join(
select distinct 
RNAME, ENAME

from [dbo].[RELATIONSHIPS]) r2
on r1.RNAME = r2.RNAME
where r1.ENAME <> r2.ENAME

order by r1.rname

---

我将如何修复代码以便只返回1行？

您可以将

行数（）

与

条件聚合一起使用：

with cte as  (
  select rname, ename, row_number() over (partition by rname order by ename) rn
  from relationships
  )
select rname, 
  max(case when rn = 1 then ename end) ename1,
  max(case when rn = 2 then ename end) ename2
from cte
group by rname



如果只有两个，那么就这样做。又短又甜

SELECT  rname,
        MIN(ename) ename1,
        MAX(ename) ename2
FROM relationships
GROUP BY rname

在甲骨文中

 select * from 
 (select rname,ename,
 RANK() over (partition by rname order by ename) Id
 FROM relationships)
 PIVOT(MAX(ename) for Id in (1 as ename1, 2 as ename2))

好的，这就解决了，以前没见过cte。谢谢@user2146212--np、cte是
公共表表达式
--有点像临时视图。解决方案的关键是使用
行编号（）
建立分组。
 select * from 
 (select rname,ename,
 RANK() over (partition by rname order by ename) Id
 FROM relationships)
 PIVOT(MAX(ename) for Id in (1 as ename1, 2 as ename2))