在SQL中连接表上的两列
我有一个很容易理解的问题,但对我来说,实现起来并不是那么简单 我有一个名为时间的表:在SQL中连接表上的两列,sql,Sql,我有一个很容易理解的问题,但对我来说,实现起来并不是那么简单 我有一个名为时间的表: ----------------------------------- DAY TIME1 TIME2 ----------------------------------- 1 08.00 09.40 1 09.40 10.00 1 10.00 11.40 2 08.00 08.50 2 0
-----------------------------------
DAY TIME1 TIME2
-----------------------------------
1 08.00 09.40
1 09.40 10.00
1 10.00 11.40
2 08.00 08.50
2 08.50 10.40
----------------------------------
我想要的是:
-------------------
DAY TIME
-------------------
1 08.00
1 09.40
1 10.00
1 11.00
2 08.00
2 08.50
2 10.40
------------------
我尝试过以下代码:
SELECT DISTINCT sub.val FROM (
SELECT Time1 AS val FROM Time
UNION ALL
SELECT Time2 AS val FROM Time
) AS sub
它只返回时间列。我不知道是否要加入“Day”专栏。当我试图在“DISTINCT sub.val”之后添加“Day”时,它出现了错误。怎么做
非常感谢。试试这个
SELECT DISTINCT sub.Day, sub.val as Time FROM (
SELECT Day, Time1 AS val FROM Time
UNION ALL
SELECT Day, Time2 AS val FROM Time
) AS sub
SELECT DISTINCT *
FROM (
SELECT day, time1 FROM Time
UNION ALL SELECT day, time2 FROM Time
) AS x
ORDER BY x.day
这可能有助于:
SELECT
DAY,
TIME1
FROM
YourTable AS T
UNION
SELECT
DAY,
TIME2
FROM
YourTable AS T
ORDER BY DAY,TIME1
@所有人:谢谢你所有的回答。用不同的方法解决这个问题确实帮了我很大的忙,并且产生了相同的价值非常感谢你的回答。:)非常感谢你的回答。:)非常感谢你的回答。:)非常感谢你的回答。:)
SELECT
DAY,
TIME1
FROM
YourTable AS T
UNION
SELECT
DAY,
TIME2
FROM
YourTable AS T
ORDER BY DAY,TIME1