Sql 是否在查询中保存select子句的结果以在同一查询中重用？

我想创建一个查询，显示等于特定值的列的计数，但只显示Microsoft SQL Server中此计数正好为2的结果

这就是我到目前为止所做的：

SELECT Menu.id,
       (
        select count(*)
        from (values (Menu.item1, Menu.item2, Menu.item3) as v(col)
        where v.col = 'banana'
       ) as numBananas
FROM Menu
WHERE (
       select count(*)
       from (values (Menu.item1, Menu.item2, Menu.item3) as v(col)
       where v.col = 'banana'
      ) = 2;

有没有办法避免select子句和WHERE子句中多余的select count*语句？我尝试了以下方法，但不起作用：

SELECT Menu.id,
       (
        select count(*)
        from (values (Menu.item1, Menu.item2, Menu.item3) as v(col)
        where v.col = 'banana'
       ) as numBananas
FROM Menu
WHERE
    numBananas = 2;

---

只需添加一个额外的查询级别即可使用任何子查询结果，例如

我还纠正了as vcol的语法错误

---

除了如图所示使用派生表/外部查询作为Dale之外，还可以使用交叉应用

顺便说一下，您最初的查询vcol不正确。我想应该是这样

from (
    values (Menu.item1), (Menu.item2), (Menu.item3)
) as v(col)

或者如果您更喜欢CTE方法

为什么要取消PIVOT？只要做：

select m.*
from menu m
where ((case when m.item1 = 'banana' then 1 else 0 end) +
       (case when m.item2 = 'banana' then 1 else 0 end) +
       (case when m.item3 = 'banana' then 1 else 0 end)
      ) = 2;

如果要取消PIVOT，可以使用子查询：

select m.*
from menu m cross apply
     (select count(*) as cnt
      from (values (m.item1), (m.item2), (m.item3)) v(item)
      where item = 'banana'
     ) x
where cnt = 2;

---

如果计数不等于2怎么办？结果是什么？@Squirrel如果计数不是2，则不包括该行。所以numBananas应该为每行=2。您有任何样本数据吗？

; with cte as
(
    SELECT  Menu.id,
        (
            select  count(*)
            from (
                values (Menu.item1), (Menu.item2), (Menu.item3)
            ) as v(col)
            where   v.col = 'banana'
        ) as numBananas
    FROM    Menu
) 
select  *
from    cte
WHERE   numBananas = 2

select m.*
from menu m
where ((case when m.item1 = 'banana' then 1 else 0 end) +
       (case when m.item2 = 'banana' then 1 else 0 end) +
       (case when m.item3 = 'banana' then 1 else 0 end)
      ) = 2;

select m.*
from menu m cross apply
     (select count(*) as cnt
      from (values (m.item1), (m.item2), (m.item3)) v(item)
      where item = 'banana'
     ) x
where cnt = 2;