Sql (it) 开始 设置@counter=1 更新tbl_计数器设置计数器=1 结束 从Employees2中选择@Editor=Name，其中id=@counter 选择top 1 newid（）作为unirow、t1.name编辑器、t2.name Contributor1、， t3.姓名出资人2、t4.姓名出资人3、t5.姓名出资人4 来自员工t1、员工t2、员工t3、员工t4、员工t5 其中t1.namet2.name和t1.namet3.name和t1.namet4.name和t1.namet5.name 和t2.namet1.name和t2.namet3.name和t2.namet4.name和t2.namet5.name 和t3.namet2.name和t3.namet1.name和t3.namet4.name和t3.namet5.name 和t4.namet2.name和t4.namet3.name和t4.namet1.name和t4.namet5.name 和t5.namet2.name和t5.namet3.name和t5.namet4.name和t5.namet1.name 和t1.name=@Editor unirow订购

结束

首先，在给定约束的情况下，编辑器不是随机的。最初的顺序是随机的，但经过一个周期后，它永远不会改变。第二，编辑是否也可以为同一篇文章提供稿件？在所有10位用户都尝试过编辑之后，这个循环可能会重新开始；循环N的最后一个编辑器也可能是循环N+1的第一个编辑器。从“选择5，选择1作为编辑器，选择4作为贡献者”中可以明显看出，编辑器没有被指定为贡献者。是的，乔纳森，你是对的。我需要一个SQL查询来查询sameLooks。努力（+1）。我打赌我无法说服您使用PowershellpI真的应该跟上PowerShell的速度。。。有一天我不知道该如何感谢你…上帝保佑你和你的家人！这就是我的整个团队都在绞尽脑汁的解决方案如果你经过比利时，你可以请我喝一杯

           Editor   Cont1   Cont2     Cont3    Cont4
20-Jun   U1      U8       U9         U3       U4
21-Jun    U7      U2       U5         U6       U10
22-Jun    U3      U4       U9         U2       U8
23-Jun      U4      U8       U3          U5      U2
and so on..

struct Team 
{
    string name;
    int editorCount;
}
currentEditorList is a List of Team 
existingUserList is a List of Team 

currentEditorList = Get Current Editor List from DailyTeam
existingUserList = Get All Users from User and its editor count (may need left outer join)


todayTeam is a new Array

// populate the normal users to dailyTeam
while (todayTeam count is less than 4)
{
    randomIndex = generate a random number (from 0 to 9)
    userName = get name from existingUserNames[randomIndex]
    if (userName is not in todayTeam)
    {
       add userName to todayTeam
    }
}


sort existingUserList by its editorCount
editorName = get the first item from existingUserList
add editorName to todayTeam

SET NOCOUNT ON

DECLARE @Users TABLE (
  UserName VARCHAR(3)
  , EditorCount INTEGER
  , ContributorCount INTEGER
)

DECLARE @Solutions TABLE (
  ID INTEGER IDENTITY(1, 1)
  , Editor VARCHAR(3)
  , Contributor1 VARCHAR(3)
  , Contributor2 VARCHAR(3)
  , Contributor3 VARCHAR(3)
  , Contributor4 VARCHAR(3)
)

DECLARE @Editor VARCHAR(3)
DECLARE @Contributor1 VARCHAR(3)
DECLARE @Contributor2 VARCHAR(3)
DECLARE @Contributor3 VARCHAR(3)
DECLARE @Contributor4 VARCHAR(3)

INSERT INTO @Users
SELECT 'U1', 0, 0
UNION ALL SELECT 'U2', 0, 0
UNION ALL SELECT 'U3', 0, 0
UNION ALL SELECT 'U4', 0, 0
UNION ALL SELECT 'U5', 0, 0
UNION ALL SELECT 'U6', 0, 0
UNION ALL SELECT 'U7', 0, 0
UNION ALL SELECT 'U8', 0, 0
UNION ALL SELECT 'U9', 0, 0
UNION ALL SELECT 'U0', 0, 0

/* Keep Generating combinations until at least one user has been editor for 10 times */
WHILE NOT EXISTS (SELECT * FROM @Solutions WHERE ID = 30)
BEGIN
  SELECT  TOP 1 @Editor = u.UserName
  FROM    @Users u
          INNER JOIN (
            SELECT  EditorCount = MIN(EditorCount)
            FROM    @Users
          ) ec ON ec.EditorCount = u.EditorCount
  ORDER BY NEWID()
  UPDATE @Users SET EditorCount = EditorCount + 1 WHERE UserName = @Editor
  INSERT INTO @Solutions VALUES (@Editor, NULL, NULL, NULL, NULL)  

  SELECT  TOP 1 @Contributor1 = u.UserName
  FROM    @Users u
          INNER JOIN (
            SELECT  ContributorCount = MIN(ContributorCount)
            FROM    @Users
          ) ec ON ec.ContributorCount = u.ContributorCount
  WHERE   UserName <> @Editor
  ORDER BY NEWID()
  UPDATE @Users SET ContributorCount = ContributorCount + 1 WHERE UserName = @Contributor1
  UPDATE @Solutions SET Contributor1 = @Contributor1 WHERE Contributor1 IS NULL

  SELECT  TOP 1 @Contributor2 = u.UserName
  FROM    @Users u
          INNER JOIN (
            SELECT  ContributorCount = MIN(ContributorCount)
            FROM    @Users
          ) ec ON ec.ContributorCount = u.ContributorCount
  WHERE   UserName NOT IN (@Editor, @Contributor1)
  ORDER BY NEWID()
  UPDATE @Users SET ContributorCount = ContributorCount + 1 WHERE UserName = @Contributor2
  UPDATE @Solutions SET Contributor2 = @Contributor2 WHERE Contributor2 IS NULL

  SELECT  TOP 1 @Contributor3 = u.UserName
  FROM    @Users u
          INNER JOIN (
            SELECT  ContributorCount = MIN(ContributorCount)
            FROM    @Users
          ) ec ON ec.ContributorCount = u.ContributorCount
  WHERE   UserName NOT IN (@Editor, @Contributor1, @Contributor2)
  ORDER BY NEWID()
  UPDATE @Users SET ContributorCount = ContributorCount + 1 WHERE UserName = @Contributor3
  UPDATE @Solutions SET Contributor3 = @Contributor3 WHERE Contributor3 IS NULL

  SELECT  TOP 1 @Contributor4 = u.UserName
  FROM    @Users u
          INNER JOIN (
            SELECT  ContributorCount = MIN(ContributorCount)
            FROM    @Users
          ) ec ON ec.ContributorCount = u.ContributorCount
  WHERE   UserName NOT IN (@Editor, @Contributor1, @Contributor2, @Contributor3)
  ORDER BY NEWID()
  UPDATE @Users SET ContributorCount = ContributorCount + 1 WHERE UserName = @Contributor4
  UPDATE @Solutions SET Contributor4 = @Contributor4 WHERE Contributor4 IS NULL

END

SELECT * FROM @Solutions
SELECT * FROM @Users

DECLARE @counter number
DECLARE @limit number
DECLARE @Editor varchar(100)


select @limit=count(*) from Employees

select @counter=counter+1 from tbl_counter

IF(@counter>@limit)
begin
     set @counter=1
     update tbl_counter set counter=1
end

select @Editor=Name from Employees2 where id=@counter

select  top 1 newid() as unirow,t1.name Editor,t2.name Contributor1,
t3.name Contributor2,t4.name Contributor3,t5.name Contributor4
from Employees t1,Employees t2,Employees t3,Employees t4,Employees t5
where t1.name<>t2.name and t1.name<>t3.name and t1.name<>t4.name and t1.name<>t5.name
and t2.name<>t1.name and t2.name<>t3.name and t2.name<>t4.name and t2.name<>t5.name
and t3.name<>t2.name and t3.name<>t1.name and t3.name<>t4.name and t3.name<>t5.name
and t4.name<>t2.name and t4.name<>t3.name and t4.name<>t1.name and t4.name<>t5.name
and t5.name<>t2.name and t5.name<>t3.name and t5.name<>t4.name and t5.name<>t1.name
and t1.name=@Editor
order by unirow