Sql 按日期分组，不含时间

我想知道，在计算日期时，是否有办法将2014-01-26 05:39:29.000和2014-01-26 07:45:31.000的日期分组为一天。我目前有下面的代码，只是根据它们唯一的日期时间对它们进行分组

    SELECT ETK_ExpirationDateTime, COUNT(*) as TotalRows
    FROM History_Action 
    WHERE [State] = 4
    GROUP BY ETK_ExpirationDateTime
    ORDER BY ETK_ExpirationDateTime 

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我可以做些什么来让上面的两个日期显示为一行，总金额是多少？

您可以使用日期转换：

SELECT CAST(ETK_ExpirationDateTime AS DATE) AS DATE, COUNT(*) as TotalRows
FROM History_Action 
WHERE [State] = 4
GROUP BY CAST(ETK_ExpirationDateTime AS DATE)
ORDER BY 1

SELECT CONVERT(date, ETK_ExpirationDateTime) as ExpirationDateTime, COUNT(*) as TotalRows
FROM History_Action 
WHERE [State] = 4
GROUP BY CONVERT(date, ETK_ExpirationDateTime)
ORDER BY CONVERT(date, ETK_ExpirationDateTime) 

这仅适用于SQL 2008或更高版本。对于较旧版本的SQL，您可以使用以下一些棘手的操作：

SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, ETK_ExpirationDateTime)) as ExpirationDateTime, COUNT(*) as TotalRows
FROM History_Action 
WHERE [State] = 4
GROUP BY DATEADD(dd, 0, DATEDIFF(dd, 0, ETK_ExpirationDateTime))
ORDER BY DATEADD(dd, 0, DATEDIFF(dd, 0, ETK_ExpirationDateTime))

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您使用的是哪种数据库管理系统？sql server mysqlI正在使用sql server可能与^I重复。我最初尝试使用它，但在筛选某个列时无法确定如何使用。是的，但请执行。