如何合并SQL查询的两个结果

我正在尝试将两个sql查询的结果合并为一个

问题1：

SELECT COUNT(class) as show, year
FROM lee
where class = 'Show'
GROUP BY year

结果

show         year
185          2016
296          2020
655          2019

   movie           year
    556          2016
    987          2020
    690          2019

问题2

SELECT COUNT(class) as movie, year
FROM lee
where class = 'movie'
GROUP BY year

结果

show         year
185          2016
296          2020
655          2019

   movie           year
    556          2016
    987          2020
    690          2019

我如何实现这样的目标：

        movie          show           year
        556            185           2016
        987            296           2020
        690            655           2019

---

使用条件聚合：

SELECT SUM(CASE WHEN class = 'show' THEN 1 ELSE 0 END) as show,
       SUM(CASE WHEN class = 'movie' THEN 1 ELSE 0 END) as movie,
       year
FROM lee
GROUP BY year;

---

您可以使用

case when

语句选择要计数的类

SELECT count(CASE WHEN class = 'movie' THEN 1 END) as movie,
       count(CASE WHEN class = 'show' THEN 1 END) as show,
       year
FROM lee
GROUP BY year;

---

我的解决方案不是最漂亮的，但它是给另一个选择

SELECT m.movie, s.show, m.YEAR FROM
(SELECT COUNT(1) AS movie, YEAR FROM LEE WHERE CLASS = 'movie' GROUP BY YEAR) m
JOIN (SELECT COUNT(1) AS show, YEAR FROM LEE WHERE CLASS = 'show' GROUP BY YEAR) s 
ON (s.YEAR = m.YEAR);