SQL Server：为连续日期跨多行创建唯一键

我有一组用于用户启动和停止程序的数据。我需要确定每个实例的总运行时间。但是，如果程序在同一天停止和启动，我需要它是连续的

最终结果应该是：

User    Start      End        EventId
--------------------------------------
X       1/1/2016   1/1/2016   1
X       1/1/2016   1/5/2016   1
X       1/5/2016   1/10/2016  1
X       1/10/2016  1/13/2016  1
X       12/20/2016 12/26/2016 2
Y       01/01/2016 01/01/2016 3
Y       01/01/2016 01/02/2016 3
Y       01/04/2016 01/10/2016 4

或：

但我想如果有人能帮我把它们正确地分组，我就能很容易地处理好

下表是我获得结果的程度：

User    Start   End         LagStart      LagStop
-------------------------------------------------
X   1/1/2016    1/1/2016    Startgroup  
X   1/1/2016    1/5/2016    Follow  
X   1/5/2016    1/10/2016   Follow  
X   1/10/2016   1/13/2016   Follow        StopGroup
X   12/20/2016  12/26/2016  StartGroup    StopGroup
X   12/26/2016  12/30/2016  Startgroup    StopGroup
Y   01/01/2016  01/01/2016  StartGroup    
Y   01/01/2016  01/02/2016  StartGroup    StopGroup
Y   01/04/2016  01/10/2016  StartGroup    StopGroup

我在创建新的唯一ID时遇到了难题，该ID从每个Startgroup开始，到每个Stopgroup结束

如果有助于查看这组数据的累积，请参见以下内容：

select
    a.user_start_key as firstStartKey, 
    a.user_end_key as firstEndKey, 
    a.start_dt as firstStartDate,
    a.end_dt as firstDisch, 
    a.rnkkey as firstRank,
    nextRec.user_start_key as nextStart,
    nextRec.start_dt,
    nextRec.max_rank,
    case 
       when Lag(nextRec.max_rank, 1) over (order by a.rnkkey) is null 
          then 'StartGroup'
       when Lag(nextRec.max_rank, 1) over (order by a.rnkkey) in (a.rnkkey)  
          then 'Follow' 
       else 'Start' 
    end as LagStart,
    case 
       when lead(a.rnkkey, 1) over (order by a.rnkkey) is null 
          then 'StopGroup' 
       when lead(a.rnkkey, 1) over (order by a.rnkkey) <> nextRec.max_rank 
          then 'StopGroup' 
       else Null 
    end as Lagstop
from 
    #rnk1 a
inner join 
    (Select Distinct 
         user_start_key, 
         start_dt,
         --dschrg_dt,
         max(rnkkey) over (partition by user_start_key order by end_dt desc) max_rank
     from 
         #rnk1) nextRec on a.user_end_key = nextRec.user_start_key

User_u[state]\u key字段只是我为每个用户\u id按日期构建一个唯一的key，因为有多个用户，我需要将它们单独分组

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如果我需要进一步澄清，请让我知道。感谢所有能够提供帮助的人。

下面是一个使用累积总和计算排名的示例。 这样排名就可以用来分组了。

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您在所需的输出中有一些记录，其中用户为Y，但您的表中没有任何值为Y的用户？抱歉，我的输入错误。假设可以有任意数量的用户。我已经更新了示例结果集。

select
    a.user_start_key as firstStartKey, 
    a.user_end_key as firstEndKey, 
    a.start_dt as firstStartDate,
    a.end_dt as firstDisch, 
    a.rnkkey as firstRank,
    nextRec.user_start_key as nextStart,
    nextRec.start_dt,
    nextRec.max_rank,
    case 
       when Lag(nextRec.max_rank, 1) over (order by a.rnkkey) is null 
          then 'StartGroup'
       when Lag(nextRec.max_rank, 1) over (order by a.rnkkey) in (a.rnkkey)  
          then 'Follow' 
       else 'Start' 
    end as LagStart,
    case 
       when lead(a.rnkkey, 1) over (order by a.rnkkey) is null 
          then 'StopGroup' 
       when lead(a.rnkkey, 1) over (order by a.rnkkey) <> nextRec.max_rank 
          then 'StopGroup' 
       else Null 
    end as Lagstop
from 
    #rnk1 a
inner join 
    (Select Distinct 
         user_start_key, 
         start_dt,
         --dschrg_dt,
         max(rnkkey) over (partition by user_start_key order by end_dt desc) max_rank
     from 
         #rnk1) nextRec on a.user_end_key = nextRec.user_start_key

-- Using a table variable for easy testing
declare @T table (id int identity(1,1) primary key, [User] varchar(8), startdate date, enddate date);
-- Sample data
insert into @T ([User], startdate, enddate) values
 ('X','2018-01-01','2018-01-01')
,('X','2018-01-01','2018-01-05')
,('X','2018-01-05','2018-01-10')
,('X','2018-01-10','2018-01-13')
,('X','2018-12-20','2018-12-26')
,('Y','2018-01-01','2018-01-01')
,('Y','2018-01-01','2018-01-02')
,('Y','2018-01-04','2018-01-10')
;

select 
 [User], 
 cumm_sum_rank as EventId, 
 datediff(day, min(startdate), max(enddate))+1 as DurationDays
 , min(startdate) as [Start]
 , max(enddate) as [End]
from
(
    select *, 
     sum(startdate_diff_prev_enddate) over (order by [User], startdate, enddate) as cumm_sum_rank
    from
    (
        select [User], startdate, enddate, 
         iif(startdate = lag(enddate) over (partition by [User] order by startdate, enddate),0,1) as startdate_diff_prev_enddate
        from @T
    ) as q1
) as q2
group by [User], cumm_sum_rank;