Sql 缺少关键字(ORA-00905)-Oracle案例陈述
我试图在select语句中编写case语句。由于height列为varchar2并包含字符,因此我需要按如下方式消除字符:Sql 缺少关键字(ORA-00905)-Oracle案例陈述,sql,oracle,oracle11g,case,Sql,Oracle,Oracle11g,Case,我试图在select语句中编写case语句。由于height列为varchar2并包含字符,因此我需要按如下方式消除字符: SELECT FIRST_NAME, LAST_NAME, (CASE height WHEN height LIKE '%>%' THEN -1 WHEN height LIKE '%<%' THEN -1 ELSE TO_NUMBER (height) END) AS h
SELECT FIRST_NAME,
LAST_NAME,
(CASE height
WHEN height LIKE '%>%' THEN -1
WHEN height LIKE '%<%' THEN -1
ELSE TO_NUMBER (height)
END) AS height
FROM TEMP;
选择名字,
姓,
(箱高
当高度为“%>%”时,则为-1
当高度像“%”时,请尝试以下操作
SELECT FIRST_NAME,
LAST_NAME,
(CASE
WHEN height LIKE '%>%' THEN
-1
WHEN height LIKE '%<%' THEN
-1
ELSE
TO_NUMBER(height)
END) AS height
FROM TEMP;
选择名字,
姓,
(案例
当高度为“%$>%”时
-1
当高度为“%”时,搜索的大小写表达式的语法错误:
SELECT FIRST_NAME,
LAST_NAME,
(CASE
WHEN height LIKE '%>%' THEN -1
WHEN height LIKE '%<%' THEN -1
ELSE TO_NUMBER (height)
END) AS height
FROM TEMP
;
选择名字,
姓,
(案例
当高度为“%>%”时,则为-1
当高度像“%”时
或者像“%2”这样的高度有两种大小写语法:CASE-WHEN-col-condition X-THEN-Y
和CASE-col-WHEN-condition X-THEN-Y
不要混淆它们谢谢,这很有帮助!
CASE WHEN height LIKE '%>%'
OR height LIKE '%<%'
THEN -1
ELSE TO_NUMBER (height)
END
CASE WHEN REGEXP_LIKE ( height, '[<>]' )
THEN -1
ELSE TO_NUMBER (height)
END