Sql &引用；其中；不使用join子句处理hql查询的限制

首先要澄清的是，我对数据库的使用非常糟糕，所以请不要用我的代码：p

我对使用联接和限制的hibernate查询有问题。我有一个巨大的

作业列表

，其中一些有一个

Asr

对象

queryString.append("select new commons.bo.assignment.AssignmentAssociateExtract("
    + " assignment.id, assignment.contract.assignmentStatus,"
    + " assignment.contract.beginDate, assignment.contract.endDate,"
    + " assignment.contract.contractType, assignment.organizationalData.homeCountryKey,"
    + " assignment.organizationalData.hostCountryKey," 
    + " assignment.organizationalData.homeOrgUnitKey,"
    + " assignment.associate.globalIdAssociate,"
    + " assignment.associate.localIdHome,"
    + " assignment.associate.firstName,"
    + " assignment.associate.lastName)"
    + " from Assignment assignment left join assignment.asr asr"
    + " where assignment.contract.assignmentStatus.code = 5"
    + " and asr.homeAsrElegibility is not 'X'"
    + " or asr.homeAsrElegibility is null"
);

我一步一步地创建这个查询。在此之前，我创建它时没有join子句

left join assignment.asr

，它工作得很好，但它当然没有显示没有

asr

对象的

Assignments

。在我添加了join子句之后，现在它显示了每一个

赋值

（当拥有

assignmentStatus=5

的人只有4.000条记录时，会显示10.000条记录）以及类似的限制

where assignment.contract.assignmentStatus.code = 5

不再反映在结果中

总而言之：我需要一个列表，其中包含assignmentStatus=5和asr.homeAsrElegibility！='X’。但它还需要包括assignmentStatus=5的所有分配，即使它们没有Asr对象

---

有什么想法吗？？谢谢

括号有助于澄清情况

queryString.append("select new commons.bo.assignment.AssignmentAssociateExtract("
    + " assignment.id, assignment.contract.assignmentStatus,"
    + " assignment.contract.beginDate, assignment.contract.endDate,"
    + " assignment.contract.contractType, assignment.organizationalData.homeCountryKey,"
    + " assignment.organizationalData.hostCountryKey," 
    + " assignment.organizationalData.homeOrgUnitKey,"
    + " assignment.associate.globalIdAssociate,"
    + " assignment.associate.localIdHome,"
    + " assignment.associate.firstName,"
    + " assignment.associate.lastName)"
    + " from Assignment assignment left join assignment.asr asr"
    + " where assignment.contract.assignmentStatus.code = 5"
    + " and ((asr.homeAsrElegibility is not null and asr.homeAsrElegibility is not 'X')"
    + " or (asr.homeAsrElegibility is null))"
);

---

你是对的！我试着删除

不是'X'

子句，只留下最后一个，当然，删除

或
关键字，它就工作了。谢谢