Sql 3条SELECT语句的平均值(按分组)
我试着做以下几点 我有一个表QA,其中包含以下内容:Sql 3条SELECT语句的平均值(按分组),sql,oracle,Sql,Oracle,我试着做以下几点 我有一个表QA,其中包含以下内容: TICKET_ID SKILL_ID SCORE USER ############################################### 1 10 15 USER1 1 20 5 USER1 1 30 95 USER1 2
TICKET_ID SKILL_ID SCORE USER
###############################################
1 10 15 USER1
1 20 5 USER1
1 30 95 USER1
2 40 20 USER1
2 50 40 USER1
3 60 70 USER1
3 70 15 USER1
SELECT DECODE(100 - SUM(SCORE),
100,100,
95,95,
90,90,
85,85,
80,80,
75,75,
70,70,
65,65,
60,60,
55,55,
50,50,
45,45,
40,40,
35,35,
30,30,
25,25,
20,20,
15,15,
10,10,
5,5,
0) SCORE_A1 FROM QA WHERE SKILL_ID IN(SELECT SKILL_ID FROM SKILLS WHERE AREA_ID = 1) AND TICKET_NUMBER = :P2_TICKET_NUMBER AND QA.USER = :P2_USER GROUP BY 1
桌子由以下部分组成:
SKILL_ID SKILL_NAME AREA_ID
10 SKILL1 1
20 SKILL2 1
30 SKILL3 2
40 SKILL4 2
50 SKILL5 2
60 SKILL6 3
70 SKILL7 3
TICKET_ID TICKET_NUMBER
1 AAA
2 BBB
3 CCC
和一张由以下材料制成的桌子:
SKILL_ID SKILL_NAME AREA_ID
10 SKILL1 1
20 SKILL2 1
30 SKILL3 2
40 SKILL4 2
50 SKILL5 2
60 SKILL6 3
70 SKILL7 3
TICKET_ID TICKET_NUMBER
1 AAA
2 BBB
3 CCC
QA有一个使用TICKET\u ID的FK to TICKET和一个使用SKILL\u ID的FK to SKILLS
我需要做的是:
对于表QA中的每张票证,检查每个区域的得分总和是否不超过100,如果超过,则算作0,然后计算3个结果的平均值,并根据另一张表中的票证编号分组
因此,对于每种情况,我需要计算每个区域的分数,如果>100,则0保留原始值,然后对3个值进行平均,并按票号分组
不确定这是否可行
因此,为了计算面积_1的分数,我可以做以下操作:
TICKET_ID SKILL_ID SCORE USER
###############################################
1 10 15 USER1
1 20 5 USER1
1 30 95 USER1
2 40 20 USER1
2 50 40 USER1
3 60 70 USER1
3 70 15 USER1
SELECT DECODE(100 - SUM(SCORE),
100,100,
95,95,
90,90,
85,85,
80,80,
75,75,
70,70,
65,65,
60,60,
55,55,
50,50,
45,45,
40,40,
35,35,
30,30,
25,25,
20,20,
15,15,
10,10,
5,5,
0) SCORE_A1 FROM QA WHERE SKILL_ID IN(SELECT SKILL_ID FROM SKILLS WHERE AREA_ID = 1) AND TICKET_NUMBER = :P2_TICKET_NUMBER AND QA.USER = :P2_USER GROUP BY 1
要计算面积_2的分数,请执行相同的操作,但更改WHERE条件(此时面积_ID=2):
并计算面积_3的分数,相同的事情,但改变了WHERE条件(其中面积_ID=3):
每个块都给出一个值作为输出
我试图实现的是将3个块的平均值按票号输出
我试图将3个区块相加,但不允许:
SELECT DECODE(100 - SUM(SCORE),
100,100,
95,95,
90,90,
85,85,
80,80,
75,75,
70,70,
65,65,
60,60,
55,55,
50,50,
45,45,
40,40,
35,35,
30,30,
25,25,
20,20,
15,15,
10,10,
5,5,
0) SCORE_A1 FROM QA WHERE SKILL_ID IN(SELECT SKILL_ID FROM SKILLS WHERE AREA_ID = 1) AND TICKET_NUMBER = :P2_TICKET_NUMBER AND QA.USER = :P2_USER GROUP BY 1
+
SELECT DECODE(100 - SUM(SCORE),
100,100,
95,95,
90,90,
85,85,
80,80,
75,75,
70,70,
65,65,
60,60,
55,55,
50,50,
45,45,
40,40,
35,35,
30,30,
25,25,
20,20,
15,15,
10,10,
5,5,
0) SCORE_A1 FROM QA WHERE SKILL_ID IN(SELECT SKILL_ID FROM SKILLS WHERE AREA_ID = 2) AND TICKET_NUMBER = :P2_TICKET_NUMBER AND QA.USER = :P2_USER GROUP BY 1
+
SELECT DECODE(100 - SUM(SCORE),
100,100,
95,95,
90,90,
85,85,
80,80,
75,75,
70,70,
65,65,
60,60,
55,55,
50,50,
45,45,
40,40,
35,35,
30,30,
25,25,
20,20,
15,15,
10,10,
5,5,
0) SCORE_A1 FROM QA WHERE SKILL_ID IN(SELECT SKILL_ID FROM SKILLS WHERE AREA_ID = 3) AND TICKET_NUMBER = :P2_TICKET_NUMBER AND QA.USER = :P2_USER GROUP BY 1
谢谢请尝试以下查询:
SELECT
AREAS_SCORES.USER,
AREAS_SCORES.TICKET_ID,
AREAS_SCORES.TICKET_NUMBER,
AVG(CASE
WHEN AREAS_SCORES.AREA_SUM_SCORE > 100 THEN 0
ELSE AREAS_SCORES.AREA_SUM_SCORE
END) AVG_SCORE
FROM
(
SELECT
QA.USER,
QA.TICKET_ID,
QA.TICKET_NUMBER,
SKILLS.AREA_ID,
SUM(QA.SCORE) AREA_SUM_SCORE
FROM
QA
INNER JOIN SKILLS ON SKILLS.SKILL_ID = QA.SKILL_ID
INNER JOIN TICKETS ON TICKETS.TICKET_ID = QA.TICKET_ID
GROUP BY
QA.USER,
QA.TICKET_ID,
QA.TICKET_NUMBER,
SKILLS.AREA_ID
) AREAS_SCORES
子查询为每个用户的每个票证计算每个区域内的分数总和。然后再次聚合信息以计算平均值,但有一个限制,即当特定区域的得分总和超过100
,则应将其计算为0
我希望它能在某种程度上有所帮助(假设我很了解您的问题)。您只需一次选择即可完成这一切。您必须将
总和
与案例
结合起来,如下所示:
SELECT T.TICKET_NUMBER,
SUM(CASE WHEN AREA_ID = 1 THEN QA.SCORE ELSE 0 END) SCORE_A1,
SUM(CASE WHEN AREA_ID = 2 THEN QA.SCORE ELSE 0 END) SCORE_A2,
SUM(CASE WHEN AREA_ID = 3 THEN QA.SCORE ELSE 0 END) SCORE_A3
FROM QA INNER JOIN SKILLS S ON QA.SKILL_ID = S.SKILL_ID
INNER JOIN TICKETS T ON QA.TICKET_ID = T.TICKET_ID
WHERE QA.USER = :P2_USER GROUP BY T.TICKET_NUMBER
现在,要应用附加条件以确保总和不超过100,请使用外部查询:
SELECT TICKET_NUMBER,
CASE WHEN SCORE_A1 > 100 THEN 0 ELSE SCORE_A1 END SCORE_A1,
CASE WHEN SCORE_A2 > 100 THEN 0 ELSE SCORE_A2 END SCORE_A2,
CASE WHEN SCORE_A3 > 100 THEN 0 ELSE SCORE_A3 END SCORE_A3
FROM
(
SELECT T.TICKET_NUMBER,
SUM(CASE WHEN AREA_ID = 1 THEN QA.SCORE ELSE 0 END) SCORE_A1,
SUM(CASE WHEN AREA_ID = 2 THEN QA.SCORE ELSE 0 END) SCORE_A2,
SUM(CASE WHEN AREA_ID = 3 THEN QA.SCORE ELSE 0 END) SCORE_A3
FROM QA INNER JOIN SKILLS S ON QA.SKILL_ID = S.SKILL_ID
INNER JOIN TICKETS T ON QA.TICKET_ID = T.TICKET_ID
WHERE QA.USER = :P2_USER GROUP BY T.TICKET_NUMBER
) TIX
最后,如果您需要这三个分数的平均值,请使用其他级别的外部查询:
SELECT TICKET_NUMBER,
SCORE_A1,
SCORE_A2,
SCORE_A3,
(SCORE_A1+SCORE_A2+SCORE_A3)/3 AVG_SCORE
FROM
(
SELECT TICKET_NUMBER,
CASE WHEN SCORE_A1 > 100 THEN 0 ELSE SCORE_A1 END SCORE_A1,
CASE WHEN SCORE_A2 > 100 THEN 0 ELSE SCORE_A2 END SCORE_A2,
CASE WHEN SCORE_A3 > 100 THEN 0 ELSE SCORE_A3 END SCORE_A3
FROM
(
SELECT T.TICKET_NUMBER,
SUM(CASE WHEN AREA_ID = 1 THEN QA.SCORE ELSE 0 END) SCORE_A1,
SUM(CASE WHEN AREA_ID = 2 THEN QA.SCORE ELSE 0 END) SCORE_A2,
SUM(CASE WHEN AREA_ID = 3 THEN QA.SCORE ELSE 0 END) SCORE_A3
FROM QA INNER JOIN SKILLS S ON QA.SKILL_ID = S.SKILL_ID
INNER JOIN TICKETS T ON QA.TICKET_ID = T.TICKET_ID
WHERE QA.USER = :P2_USER GROUP BY T.TICKET_NUMBER
) TIX
) MORE_TIX
请注意,对于解码表达式,如果您的100和(分数)不能被5整除,则结果将为零。即,如果100-总和(分数)=73,则为0。这是您所期望的吗?您能确认您正在使用Oracle(
解码
功能)吗?您好,谢谢您的回复,我正在使用Oracle 12c,所以是的,这是Oracle解码功能。您将如何检查而不是使用解码功能?我已经看到,您可以在select中嵌入一个案例,但主要问题是,我不知道如何将所有内容放在一起,以便获得每个票号的3个区域的平均值you@ChrisA. 嗨,请在下面找到答案。我希望你能得到需要的帮助。Regard请在问题中添加信息,方法是对其进行修改,而不是将其隐藏在评论中,以免在混乱中丢失。它还有助于,特别是在SQL中,为您正在使用的特定DBMS包含一个标记,因为它们之间的功能和语法各不相同。另外,没有必要大声说出问题标题中的信息。嗨@Chris。我真的很高兴它可能有用。问候:)