包含左联接的SQL Oracle更新

我想对select查询的结果执行更新

SELECT
    a.reason,
    n.note
FROM applications a
LEFT JOIN notes n on n.app_id = a.app_id
    AND n.note LIKE '%old%'
WHERE a.code = 'run' AND a.reason IS NULL

我想我可以单独执行这些更新，在更新中包装select，但是我得到错误ORA-01733:此处不允许虚拟列。如何执行这些更新

UPDATE (
    SELECT
        a.reason AS Reason
    FROM applications a
    LEFT JOIN notes n on n.app_id = a.app_id
        AND n.note LIKE '%old%'
    WHERE a.code = 'run' AND a.reason IS NULL
) SET Reason = null

UPDATE (
    SELECT
        n.note AS Note
    FROM applications a
    LEFT JOIN notes n on n.app_id = a.app_id
        AND n.note LIKE '%old%'
    WHERE a.code = 'run' AND a.reason IS NULL
) SET Note = null

---

不能同时更新这两个表。您需要两个不同的update语句，如下所示：

UPDATE NOTES N
   SET
    NOTE = NULL
 WHERE EXISTS (
    SELECT 1
      FROM APPLICATIONS A
     WHERE N.APP_ID = A.APP_ID
       AND A.CODE = 'run'
       AND A.REASON IS NULL
)
AND N.NOTE LIKE '%old%'

更新

应用程序

表非常容易，因为

应用程序

表中具有

a.code='run'和a.reason为NULL的所有记录都将出现在
选择
查询中

UPDATE APPLICATIONS A
   SET
    REASON = NULL
 WHERE A.CODE = 'run'
   AND A.REASON IS NULL;

要更新
NOTES
表，可以使用
EXISTS
子句，如下所示：

UPDATE NOTES N
   SET
    NOTE = NULL
 WHERE EXISTS (
    SELECT 1
      FROM APPLICATIONS A
     WHERE N.APP_ID = A.APP_ID
       AND A.CODE = 'run'
       AND A.REASON IS NULL
)
AND N.NOTE LIKE '%old%'

您必须先更新
NOTES
表，然后更新
APPLICATIONS
表，就像在更新
NOTES
表时使用条件
A一样。原因为空
但在更新
APPLICATIONS
表时，您正在更新
原因
列