SQL如何根据目标源上的数量将数量拆分为多行

我有两个表，我想加入其中，并显示详细的数量。 表与ITM、DIA连接，在ITM/DIA组合上，两个表中的总数量相等

我想拆分表1上的表2数量，并将表2数据与表1数据一起填充

我有以下数据供您参考，表1和表2。您可以在tableResult表中看到我的预期结果

CREATE TABLE table1
    (`ITM` varchar(5), `DIA` varchar(4), `LOC` varchar(4), `ID` varchar(3), `QTY` int)
;

INSERT INTO table1
    (`ITM`, `DIA`, `LOC`, `ID`, `QTY`)
VALUES
    ('Item1', 'DIA1', 'LOC1', 'ID1', 3),
    ('Item1', 'DIA1', 'LOC2', 'ID2', 4),
    ('Item1', 'DIA1', 'LOC2', 'ID2', 6),
    ('Item1', 'DIA2', 'LOC2', 'ID2', 6),
    ('Item1', 'DIA2', 'LOC3', 'ID3', 18),
    ('Item1', 'DIA2', 'LOC4', 'ID4', 90),
    ('Item1', 'DIA2', 'LOC4', 'ID5', 23),
    ('Item1', 'DIA3', 'LOC5', 'ID6', 50),
    ('Item1', 'DIA3', 'LOC6', 'ID7', 20),
    ('Item2', 'DIA1', 'LOC4', 'ID8', 44),
    ('Item2', 'DIA2', 'LOC5', 'ID8', 21),
    ('Item2', 'DIA3', 'LOC6', 'ID9', 20)
;


CREATE TABLE table2
    (`ITM` varchar(5), `DIA` varchar(4), `NTA` varchar(5), `QTY` int)
;

INSERT INTO table2
    (`ITM`, `DIA`, `NTA`, `QTY`)
VALUES
    ('Item1', 'DIA1', 'NTA1', 10),
    ('Item1', 'DIA1', 'NTA2', 3),
    ('Item1', 'DIA2', 'NTA3', 30),
    ('Item1', 'DIA2', 'NTA4', 7),
    ('Item1', 'DIA2', 'NTA5', 100),
    ('Item1', 'DIA3', 'NTA6', 70),
    ('Item2', 'DIA1', 'NTA7', 22),
    ('Item2', 'DIA1', 'NTA8', 20),
    ('Item2', 'DIA2', 'NTA9', 6),
    ('Item2', 'DIA2', 'NTA10', 15),
    ('Item2', 'DIA3', 'NTA11', 8),
    ('Item2', 'DIA3', 'NTA11', 12)
;


CREATE TABLE tableResult
    (`ITM` varchar(5), `DIA` varchar(4), `LOC` varchar(4), `ID` varchar(3), `QTY` int, `NTA` varchar(5), `NewQTY` int)
;

INSERT INTO tableResult
    (`ITM`, `DIA`, `LOC`, `ID`, `QTY`, `NTA`, `NewQTY`)
VALUES
    ('Item1', 'DIA1', 'LOC1', 'ID1', 3, 'NTA1', 3),
    ('Item1', 'DIA1', 'LOC2', 'ID2', 4, 'NTA1', 4),
    ('Item1', 'DIA1', 'LOC2', 'ID2', 6, 'NTA1', 3),
    ('Item1', 'DIA1', 'LOC2', 'ID2', 6, 'NTA2', 3),
    ('Item1', 'DIA2', 'LOC2', 'ID2', 6, 'NTA3', 6),
    ('Item1', 'DIA2', 'LOC3', 'ID3', 18, 'NTA3', 18),
    ('Item1', 'DIA2', 'LOC4', 'ID4', 90, 'NTA3', 6),
    ('Item1', 'DIA2', 'LOC4', 'ID4', 90, 'NTA4', 7),
    ('Item1', 'DIA2', 'LOC4', 'ID4', 90, 'NTA5', 77),
    ('Item1', 'DIA2', 'LOC4', 'ID5', 23, 'NTA5', 23),
    ('Item1', 'DIA3', 'LOC5', 'ID6', 50, 'NTA6', 50),
    ('Item1', 'DIA3', 'LOC6', 'ID7', 20, 'NTA6', 20),
    ('Item2', 'DIA1', 'LOC4', 'ID8', 44, 'NTA7', 22),
    ('Item2', 'DIA1', 'LOC4', 'ID8', 44, 'NTA8', 20),
    ('Item2', 'DIA2', 'LOC5', 'ID8', 21, 'NTA9', 6),
    ('Item2', 'DIA2', 'LOC5', 'ID8', 21, 'NTA10', 15),
    ('Item2', 'DIA3', 'LOC6', 'ID9', 20, 'NTA11', 8),
    ('Item2', 'DIA3', 'LOC6', 'ID9', 20, 'NTA11', 12)
;

下面是数据截图；

我可以用proc和follow cursor实现，但我想知道SQL 2014有没有简单的方法，我知道事实上，CTE递归技巧会有所帮助

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你能分享一下你的解决方案吗？非常感谢您的宝贵想法。

您只需将表1和表2的数量以单位进行分解，然后将它们并排耦合。 请注意FN_NUMBERSn，它是一个函数，只返回一列从1到n的数字，你需要它在你的数据库中，有很多方法可以做到这一点，只是谷歌理货表或。 我使用以下方法：

CREATE FUNCTION FN_NUMBERS(
     @MAX INT
)
RETURNS @N TABLE (N INT NOT NULL PRIMARY KEY)  
BEGIN
     WITH
       Pass0 as (select '1' as C union all select '1'),       --2 rows
       Pass1 as (select '1' as C from Pass0 as A, Pass0 as B),--4 rows
       Pass2 as (select '1' as C from Pass1 as A, Pass1 as B),--16 rows
       Pass3 as (select '1' as C from Pass2 as A, Pass2 as B),--256 rows
       Pass4 as (select TOP (@MAX) '1' as C from Pass3 as A, Pass3 as B)    --65536 rows
       ,Tally as (select TOP (@MAX) '1' as C from Pass4 as A, Pass2 as B, Pass1 as C)  --4194304 rows
       --,Tally as (select TOP (@MAX) '1' as C from Pass4 as A, Pass3 as B)               --16777216 rows
       --,Tally as (select TOP (@MAX) '1' as C from Pass4 as A, Pass4 as B)               --4294836225 rows
     INSERT INTO @N
     SELECT TOP (@MAX) ROW_NUMBER() OVER(ORDER BY C) AS N
     FROM Tally
     RETURN
END

回到sql

;with
t1 as (
    select *, ROW_NUMBER() over (partition by itm,dia order by loc,id) rn      
    from table1 t1
    join FN_NUMBERS(500) on n<=t1.qty
),
t2 as (
    select *, ROW_NUMBER() over (partition by itm,dia order by nta) rn      
    from table2 t2
    join FN_NUMBERS(500) on n<=t2.qty
),
t3 as (
    select t1.itm, t1.dia, t1.loc, t1.id, t1.qty, t2.nta, count(t1.n) NewQTY
    from  t1
    join  t2 on t1.itm=t2.itm and t1.dia = t2.dia and t1.rn=t2.rn
    group by t1.itm, t1.dia, t1.loc, t1.id, t1.qty, t2.nta
)
select * 
from t3
order by 1,2,3,4,5,6

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您使用的是哪种数据库管理系统？还有：@a_horse_，最后一行没有名字，我认为它是Sql Server-2014@Shnugo：但问题中的DDL对于SQL无效Server@a_horse_with_no_name啊，我明白了，有背虱。。。因此，亲爱的用户459295，请澄清DBMS供应商和版本，如果我做错了，请更正标记…@Shnugo谢谢编辑我的帖子，我不知道如何那样起草，标记现在很好。我正在尝试SQL Server 2014。我希望你们都清楚我的问题。