Sql 如何在没有聚合的情况下实现轴心，这是可能的吗？

我想按以下顺序重新排列表中的行和列。这可能吗？如何实现

这是我所期望的结果。我怎样才能做到这一点

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如果您的每一行都有多个值，那么在没有聚合功能的情况下您希望得到什么？

如果每行只有一个值，那么使用sum、min、max或avg聚合函数就没有关系了。
像这样（在oracle中）：

带示例的可执行版本：

select row_id, 'C1', 'C2', 'C3'
  from (select 1 table_id, 'C1' Column_id, 1 Row_id, 20000 "value"          from dual        union all
    select 1 table_id, 'C2' Column_id, 1 Row_id, 30000 "value"          from dual        union all
    select 1 table_id, 'C3' Column_id, 1 Row_id, 25000 "value"          from dual        union all
    select 1 table_id, 'C1' Column_id, 2 Row_id, 80200 "value"          from dual        union all
    select 1 table_id, 'C2' Column_id, 2 Row_id, 50000 "value"          from dual        union all
    select 1 table_id, 'C3' Column_id, 2 Row_id, 95000 "value" from dual) 
pivot(max("value") for column_id in('C1', 'C2','C3'))

编辑：我在没有编辑器的情况下编写了这篇文章&没有运行SQL。我希望你明白了

select row_id, 'C1', 'C2', 'C3'
  from (select 1 table_id, 'C1' Column_id, 1 Row_id, 20000 "value"          from dual        union all
    select 1 table_id, 'C2' Column_id, 1 Row_id, 30000 "value"          from dual        union all
    select 1 table_id, 'C3' Column_id, 1 Row_id, 25000 "value"          from dual        union all
    select 1 table_id, 'C1' Column_id, 2 Row_id, 80200 "value"          from dual        union all
    select 1 table_id, 'C2' Column_id, 2 Row_id, 50000 "value"          from dual        union all
    select 1 table_id, 'C3' Column_id, 2 Row_id, 95000 "value" from dual) 
pivot(max("value") for column_id in('C1', 'C2','C3'))

Select Row_ID,
     Min(Case DBColumnName When 'c1' Then Value End) c1,
     Min(Case DBColumnName When 'c2' Then Value End) c2,
     Min(Case DBColumnName When 'c3' Then Value End) c3
   From table
   Group By Row_ID