Sql 如何对每种类型的几个列值求和并计算百分比？

我有下面的查询，它给了我三列数据-类型，金额和总数为本周使用周数列

以下是我通过上述查询得到的结果：

type    amount      total
---------------------------
PROC1    450         1768
PROC1    900         123
PROC1    450         456
PROC2    8840        99897
PROC2    1490        2223
PROC2    8840        9876
PROC3    1900        23456
PROC3    1600        12498
PROC3    1600        28756

问题陈述

现在，我需要使用以下公式计算每种类型的百分比：

对于每种类型，sumtotal-sumamount/sumamount。 因此，对于PROC1类型，所有“总计”列之和-所有“金额”列之和/所有“金额”列之和。 PROC2和PROC3也是如此。 此外，我还需要额外的总体类型，这将是所有PROC1+PROC2+PROC3值的总和。 最后，我应该看到以下输出：

type    sum_amount   sum_total   percentage
----------------------------------------------
PROC1    1800         2347          0.3038
PROC2    10330      111996          9.841
PROC3    5100        64710          11.688
OVERALL  17230      179053          9.3919

---

这可以在红移中实现吗？

假设您拥有的表被称为my_table。这将是您获得的表的继续：您可以使用with函数继续逻辑：

SELECT *, sum_total/ sum_amounT - 1 percentage
FROM (
  SELECT DISTINCT type, 
         0.0 + SUM(amount) sum_amount, 
         SUM(total) sum_total 
   FROM my_table
   GROUP BY type)

UNION ALL

SELECT *, sum_total/ sum_amount - 1 percentage
FROM ( SELECT  'overall' type, 
              0.0 + SUM(amount) sum_amount, 
              SUM(total) sum_total 
       FROM my_table)

---

您可以将其表述为：

with t as (
      <your query here>
     )
select type, sum(amount) as amount, sum(total) as total,
       (sum(total) - sum(amount)) * 1.0 / sum(amount) as ratio
from t
group by type, amount, total
union all
select 'Overall', sum(amount), sum(total),
       (sum(total) - sum(amount)) * 1.0 / sum(amount) as ratio
from t;

实际上，这将使整个列排在最后。但是，除非您通过添加订单，否则不能保证这一点

with t as (
      <your query here>
     )
select type, sum(amount) as amount, sum(total) as total,
       (sum(total) - sum(amount)) * 1.0 / sum(amount) as ratio
from t
group by type, amount, total
union all
select 'Overall', sum(amount), sum(total),
       (sum(total) - sum(amount)) * 1.0 / sum(amount) as ratio
from t;