在sql中组合查询结果
我正在使用SQL语言。我想合并查询的结果。 这是我的代码和预期输出在sql中组合查询结果,sql,Sql,我正在使用SQL语言。我想合并查询的结果。 这是我的代码和预期输出 create table customer(name varchar,dpt varchar); insert into customer (name,dpt)VALUES ('albe','cse'); insert into customer (name,dpt)VALUES ('bine','cse'); insert into customer (name,dpt)VALUES ('alfred','ece'); i
create table customer(name varchar,dpt varchar);
insert into customer (name,dpt)VALUES ('albe','cse');
insert into customer (name,dpt)VALUES ('bine','cse');
insert into customer (name,dpt)VALUES ('alfred','ece');
insert into customer (name,dpt)VALUES ('booshan','ece');
insert into customer (name,dpt)VALUES ('antony','eee');
insert into customer (name,dpt)VALUES ('job','ece');
查询1:
select
dpt,
count(name)
from customer
where dpt='ece' or dpt='cse'
group by dpt;
| dpt | count |
|-----|-------|
| cse | 2 |
| ece | 3 |
结果:
select
dpt,
count(name)
from customer
where dpt='ece' or dpt='cse'
group by dpt;
| dpt | count |
|-----|-------|
| cse | 2 |
| ece | 3 |
我需要的结果如下:
| cse/ece | 5 |
这怎么可能?
sqlfiddle在这里:
您似乎在使用PostgreSQL(从SQLFIDLE链接可以推断出这一点) 如果是这种情况,那么您可以在外部查询中的查询上应用
array\u agg
和sum
:
SELECT array_agg(dpt), sum(cnt)
FROM (
SELECT dpt, count(name) as cnt
FROM customer
WHERE dpt='ece' OR dpt='cse'
GROUP BY dpt) t;
您似乎在使用PostgreSQL(从SQLFIDLE链接可以推断出这一点) 如果是这种情况,那么您可以在外部查询中的查询上应用
array\u agg
和sum
:
SELECT array_agg(dpt), sum(cnt)
FROM (
SELECT dpt, count(name) as cnt
FROM customer
WHERE dpt='ece' OR dpt='cse'
GROUP BY dpt) t;
您也可以使用
GROUP\u CONCAT
SELECT GROUP_CONCAT(dpt), SUM(cnt)
FROM(select
dpt,
count(name) cnt
from customer
where dpt='ece' or dpt='cse'
group by dpt) t;
您也可以使用
GROUP\u CONCAT
SELECT GROUP_CONCAT(dpt), SUM(cnt)
FROM(select
dpt,
count(name) cnt
from customer
where dpt='ece' or dpt='cse'
group by dpt) t;