Sql 将多个行合并为具有相同ID的单个行

当我对（调查的）两列执行查询时，会出现问题，因为我希望输出点为单个ID，而不是查询将ID提供的每个响应的输出分开

原始查询

select distinct _PanelistaId_,
(case when cancl_seg_vida_mr = '4' then '1' end) as cancl_seg_vida_mr,
(case when prop_seg_med_mr = '5' then '1' end) as prop_seg_med_mr
FROM [NQ_Mexico].[dbo].[tabla_sr_mr_values] 
where _PanelistaId_ = '100177354'
group by _PanelistaId_, cancl_seg_vida_mr, prop_seg_med_mr

输出是：

_PanelistaId_   cancl_seg_vida_mr   prop_seg_med_mr
100177354         NULL          NULL
100177354         NULL          1
100177354         1             NULL

但我想要的结果是：

_PanelistaId_   cancl_seg_vida_mr   prop_seg_med_mr
100177354           1               1

使用聚合：

select _PanelistaId_,
       max(case when cancl_seg_vida_mr = '4' then '1' end) as cancl_seg_vida_mr,
       max(case when prop_seg_med_mr = '5' then '1' end) as prop_seg_med_mr
from [NQ_Mexico].[dbo].[tabla_sr_mr_values] 
where _PanelistaId_ = '100177354'
group by _PanelistaId_;