SQL如何检查彼此之间是否存在一小时范围内的时间戳

我有一个如下表，其中用户事件记录为unixtime

select day, 
user_id, 
unixtime,
from_unixtime(unixtime)
from sampletable

白天 用户id unixtime 时间戳 2020-12-20 1. 1608434879 2020-12-20 03:27:59.000 2020-12-20 1. 1608468153 2020-12-20 12:42:33.000 2020-12-20 2. 1608436224 2020-12-20 03:50:24.000 2020-12-20 2. 1608437616 2020-12-20 04:13:36.000 2020-12-20 3. 1608476189 2020-12-20 14:56:29.000 2020-12-20 3. 1608505424 2020-12-20 23:03:44.000 2020-12-20 3. 1608505438 2020-12-20 23:03:58.000 2020-12-20 4. 1608463622 2020-12-20 11:27:02.000 您可以使用铅：

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对于比率，您可以除以countdistinct user_id。

用您正在使用的数据库标记您的问题。

select day, 
       count(distinct case when next_unixtime - unixtime < 60*60 then user_id end) as num_users
from (select t.*,
             lead(unixtime) over (partition by user_id, day order by unixtime) as next_unixtime
      from sampletable
     ) t
group by day;