Sql Oracle到Derby-ConnectBy，从Derby中的等效项开始

下面的问题1对于Oracle来说没有问题。我希望在Derby中执行相同的功能。我得到了问题2，作为这里要遵循的建议之一。但这仍然是一个错误。请有人帮我把这个处理掉。我该怎么办

查询1:

Select f.folder_id, f.identifier

            From FOLDER f, STOREENT se
            Where f.type = 'AttributeFolder'
            And se.storeent_id = f.storeent_id 
            And se.identifier = 'Global_CAS'
            And f.identifier = 10051 
connect by prior f.folder_id = f.parentfolder_id
start with f.identifier = 'Categories Descriptors [Global.B2C.Sales]'

with cte as (

select folder_id, f.identifier, cast(null as varchar(255)) parentfolder_id,

       0 as depth,
       se.identifier as se_identifier
       from folder f
       join storeent se on se.storeent_id = f.storeent_id
       where f.identifier = 'A'
    union all
    select f.folder_id, f.identifier, f.parentfolder_id,
       cte.depth + 1 as depth,
       se.identifier as se_identifier
    from folder f
    join storeent se on se.storeent_id = f.storeent_id
    join cte cte on f.parentfolder_id = cte.folder_id
)
Select parentfolder_id, folder_id, identifier, depth
from cte

java.sql.SQLSyntaxErrorException: Syntax error: Encountered "with" at line 1, column 1

查询2:

Select f.folder_id, f.identifier

            From FOLDER f, STOREENT se
            Where f.type = 'AttributeFolder'
            And se.storeent_id = f.storeent_id 
            And se.identifier = 'Global_CAS'
            And f.identifier = 10051 
connect by prior f.folder_id = f.parentfolder_id
start with f.identifier = 'Categories Descriptors [Global.B2C.Sales]'

with cte as (

select folder_id, f.identifier, cast(null as varchar(255)) parentfolder_id,

       0 as depth,
       se.identifier as se_identifier
       from folder f
       join storeent se on se.storeent_id = f.storeent_id
       where f.identifier = 'A'
    union all
    select f.folder_id, f.identifier, f.parentfolder_id,
       cte.depth + 1 as depth,
       se.identifier as se_identifier
    from folder f
    join storeent se on se.storeent_id = f.storeent_id
    join cte cte on f.parentfolder_id = cte.folder_id
)
Select parentfolder_id, folder_id, identifier, depth
from cte

java.sql.SQLSyntaxErrorException: Syntax error: Encountered "with" at line 1, column 1

错误1:

Select f.folder_id, f.identifier

            From FOLDER f, STOREENT se
            Where f.type = 'AttributeFolder'
            And se.storeent_id = f.storeent_id 
            And se.identifier = 'Global_CAS'
            And f.identifier = 10051 
connect by prior f.folder_id = f.parentfolder_id
start with f.identifier = 'Categories Descriptors [Global.B2C.Sales]'

with cte as (

select folder_id, f.identifier, cast(null as varchar(255)) parentfolder_id,

       0 as depth,
       se.identifier as se_identifier
       from folder f
       join storeent se on se.storeent_id = f.storeent_id
       where f.identifier = 'A'
    union all
    select f.folder_id, f.identifier, f.parentfolder_id,
       cte.depth + 1 as depth,
       se.identifier as se_identifier
    from folder f
    join storeent se on se.storeent_id = f.storeent_id
    join cte cte on f.parentfolder_id = cte.folder_id
)
Select parentfolder_id, folder_id, identifier, depth
from cte

java.sql.SQLSyntaxErrorException: Syntax error: Encountered "with" at line 1, column 1

---

目前，derby不支持递归查询，请参见（2004年开放，最后一次评论是在2014年）。不幸的是，您不能在单个查询中完成这项工作，您必须自己编写某种树遍历循环。

目前，derby不支持递归查询，请参阅（2004年开放，最后一次评论于2014年）。不幸的是，您不能在单个查询中完成这项工作，您必须自己编写某种树遍历循环