返回每个ID SQL的最小行数

我有一个很长的列表，大致如下（列名和匿名数据）

我所追求的是每列“ID”生成1行的能力，它具有最低ID2的值之和

例如，上表将变成：

ID | ID2 | Value
1  |  5  |  900
2  |  2  |  300
3  |  4  |  100
4  |  5  |  900

我尝试了几个脚本变体，但没有成功。这是我当前清除的代码：

    SELECT res.id
       , min(id2) as rdk
       ,sum(value)

  FROM x as res

    left join y as clai
    on res.id = clai.id

    left join z as cal
    on clai.col99 = cal.col99

    group by
       res.id

然而，总和是将“ID”的所有值相加，而不仅仅是最低的“ID2”

感谢您的帮助

试试这个：-

select a.ID,a.ID2, sum(Value) as Value
from
your_table_name a
inner join
(
SElect ID, min(ID2) as ID2
from your_table_name
group by ID
) b
on a.ID=b.ID and a.ID2=b.ID2
group by a.ID,a.ID2;

希望这有帮助：-）

尝试一下：

select a.*,b.value from
(select id,min(id2) as id2 
from have
group by id) a
left join
(select id,id2,sum(value) as value
from have
group by id,id2) b
on a.id=b.id and a.id2=b.id2;

我的输出：

id  |id2 |value
1   |5   |900
2   |2   |300
3   |4   |100
4   |5   |900

---

如果有任何疑问，请告诉我。

我将把我的解决方案留在这里：）

---

如果您的表名为t1：

SELECT t1.id, t1.id2, SUM(t1.value) 
FROM t1 INNER JOIN
(
 SELECT id, min(id2) minId 
 FROM t1
 GROUP BY id
) A
ON A.id = t1.id AND A.minId = t1.id2
GROUP BY t1.id, t1.id2

---

为什么

2 | 2 | 300

？是不是应该是

2 | 2 | 100

？@KobyDouek它应该是300，因为有两个ID=2的条目，ID2=2，所以它将两个值相加，如果这有意义的话？非常感谢你的帮助：）非常感谢你的帮助：）非常感谢你的帮助：）非常感谢你的帮助：）非常感谢你的帮助：）很高兴帮助：）

with ExampleData as (
  select 1 ID1,  5 ID2,   900 Value union all
  select 1 ID1,  7  ID2,  400 Value union all
  select 2 ID1,  2  ID2,  100 Value union all
  select 2 ID1,  8  ID2,  800 Value union all
  select 2 ID1,  2  ID2,  200 Value union all
  select 3 ID1,  4  ID2,  100 Value union all
  select 3 ID1,  5  ID2,  300 Value union all
  select 4 ID1,  8  ID2,  750 Value union all
  select 4 ID1,  5  ID2,  900 Value)

select ID1,
       ID2, 
       Value 
from (
   select ID1,
          ID2,
          SUM(VALUE) VALUE,
          ROW_NUMBER() OVER (partition by ID1 order by ID2) R 
   from ExampleData
   group by ID1,ID2
) T where T.R=1

SELECT t1.id, t1.id2, SUM(t1.value) 
FROM t1 INNER JOIN
(
 SELECT id, min(id2) minId 
 FROM t1
 GROUP BY id
) A
ON A.id = t1.id AND A.minId = t1.id2
GROUP BY t1.id, t1.id2