Sql Oracle-ORA-01848错误

我正在尝试执行以下查询

SELECT w.grid_no, SUM(A) 
FROM TABLE_1 w 
WHERE w.DAY between to_date((select jsow from TABLE_2 t where t.grid_no = w.grid_no and t.crop_no=90) || '-2016','DDD-YYYY') - 0 
      and to_date((select jsow from TABLE_2 t where t.grid_no = w.grid_no and t.crop_no=90) || '-2016','DDD-YYYY') + 0 + 10 - 1 
      and A > 8 
group BY w.GRID_NO

但我有一个错误

01848. 00000 -  "day of year must be between 1 and 365 (366 for leap year)"

相反，如果我在grid_no上添加一个过滤器，查询就会工作；e、 g

SELECT w.grid_no, SUM(A) 
FROM TABLE_1 w 
WHERE w.grid_no=1000  -- <---- the added filter
      and w.DAY between to_date((select jsow from TABLE_2 t where t.grid_no = w.grid_no and t.crop_no=90) || '-2016','DDD-YYYY') - 0 
      and to_date((select jsow from TABLE_2 t where t.grid_no = w.grid_no and t.crop_no=90) || '-2016','DDD-YYYY') + 0 + 10 - 1 
     and A > 8

jsow是一个朱利安日：对于给定的成对网格，表2中存储的最大值可以从1到366

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我的目标是这样：对于表1中的每个网格，我必须在表2中得到相应的jsow值，并在通过jsow指定的范围内求和A值

如果表_2中的值为null，或者表_1中的网格_id在表_2中没有与crop 90匹配的行，则子查询将返回null或无数据。无论哪种方式，最终都会得到一个无效的数据字符串

使用一些虚拟数据：

create table table_1 (grid_no, day, a) as
  select 1000, date '2016-01-01', 42 from dual
  union all select 1001, date '2016-01-02', 42 from dual
  union all select 1002, date '2016-01-03', 42 from dual
  union all select 1003, date '2016-01-04', 42 from dual;

create table table_2(grid_no, crop_no, jsow) as
  select 1000, 90, 1 from dual
  union all select 1001, 91, 367 from dual
  union all select 1002, 90, null from dual;

SELECT w.grid_no,
  (select jsow from TABLE_2 t where t.grid_no = w.grid_no and t.crop_no=90) as jsow,
  (select jsow from TABLE_2 t where t.grid_no = w.grid_no and t.crop_no=90) || '-2016' as date_string
FROM TABLE_1 w;

   GRID_NO       JSOW DATE_STRING                                  
---------- ---------- ---------------------------------------------
      1000          1 1-2016                                       
      1001            -2016                                        
      1002            -2016                                        
      1003            -2016                                        

如果尝试将其中一个字符串转换为日期，则会出现相同的错误：

select to_date('-2016', 'DDD-YYYY') from dual;

ORA-01848: day of year must be between 1 and 365 (366 for leap year)

您可以使用联接（而不是两个子查询）重写查询，这使筛选所需行稍微容易一些：

SELECT w.grid_no, SUM(w.A) 
FROM TABLE_1 w 
JOIN TABLE_2 t ON t.grid_no = w.grid_no
AND w.DAY between to_date(t.jsow || '-2016','DDD-YYYY') - 0
  AND to_date(t.jsow || '-2016','DDD-YYYY') + 9
WHERE t.crop_no=90
AND t.jsow between 1 and 366
AND w.A > 8
GROUP BY w.GRID_NO;

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内部连接意味着忽略任何没有表_2行的表_1行；jsow上的过滤器在匹配项为空时启用。您可能更希望它成为一个外部连接，这取决于您实际执行的其他操作。

错误表明您的jsow值实际上不在1和366之间？@AlexPoole我检查过：MINjsow=1，MAXjsow=366。grid_id=1000请参见第二个查询have jsow=366 grid id 1000显然具有OK jsow值，其他的一个没有。您是说从表2中选择minjsow、maxjsow，在所有网格ID中显示1和366，还是只选择1000？如果对所有id都是这样，那么在有和没有crop_no=90过滤器的情况下都是这样吗？@AlexPoole jsow=366，crop_no=90，grid_id=1000，对于crop 90，jsow是否有空值？或者表1中的网格ID在表2中没有与crop 90匹配的行？

SELECT w.grid_no, SUM(w.A) 
FROM TABLE_1 w 
JOIN TABLE_2 t ON t.grid_no = w.grid_no
AND w.DAY between to_date(t.jsow || '-2016','DDD-YYYY') - 0
  AND to_date(t.jsow || '-2016','DDD-YYYY') + 9
WHERE t.crop_no=90
AND t.jsow between 1 and 366
AND w.A > 8
GROUP BY w.GRID_NO;