Oracle SQL摘要/透视表

我有一个如下所示的数据集：

    ID      Description                     Team
    A       Missing Name; Missing Gender    Team1
    B       Missing Gender                  Team1
    C       Missing Name                    Team2
    D       Missing Name                    Team2

    Team        Missing Gender      Missing Name
    Team1       2                   1
    Team2       0                   2

       SELECT
    "Team",
    sum(case when "DQ Info" like '%Missing Gender%' then 1 ELSE 0 END) as "Missing Gender",
    sum(case when "DQ Info" like '%Missing Name%' then 1 ELSE 0 END) as "Missing Name"
    FROM
    (*)
    GROUP BY "Team"

    Description                     Team1       Team2
    Missing Name; Missing Gender    1           0
    Missing Gender                  1           0
    Missing Name                    0           2

i、 e.每个ID都有一行，带有一个文本列（说明），用于标识ID的任何问题，以及ID所属团队的名称。我设法将其总结如下：

    ID      Description                     Team
    A       Missing Name; Missing Gender    Team1
    B       Missing Gender                  Team1
    C       Missing Name                    Team2
    D       Missing Name                    Team2

    Team        Missing Gender      Missing Name
    Team1       2                   1
    Team2       0                   2

       SELECT
    "Team",
    sum(case when "DQ Info" like '%Missing Gender%' then 1 ELSE 0 END) as "Missing Gender",
    sum(case when "DQ Info" like '%Missing Name%' then 1 ELSE 0 END) as "Missing Name"
    FROM
    (*)
    GROUP BY "Team"

    Description                     Team1       Team2
    Missing Name; Missing Gender    1           0
    Missing Gender                  1           0
    Missing Name                    0           2

通过使用如下所示的case语句：

    ID      Description                     Team
    A       Missing Name; Missing Gender    Team1
    B       Missing Gender                  Team1
    C       Missing Name                    Team2
    D       Missing Name                    Team2

    Team        Missing Gender      Missing Name
    Team1       2                   1
    Team2       0                   2

       SELECT
    "Team",
    sum(case when "DQ Info" like '%Missing Gender%' then 1 ELSE 0 END) as "Missing Gender",
    sum(case when "DQ Info" like '%Missing Name%' then 1 ELSE 0 END) as "Missing Name"
    FROM
    (*)
    GROUP BY "Team"

    Description                     Team1       Team2
    Missing Name; Missing Gender    1           0
    Missing Gender                  1           0
    Missing Name                    0           2

我希望能够总结这些数据，使其看起来像这样：

    Description         Team1       Team2
    Missing Gender      2           0
    Missing Name        1           2

我知道一定有办法做到这一点，但我目前正在努力——在上述字段中仅使用“描述”而不是“团队”，结果如下：

    ID      Description                     Team
    A       Missing Name; Missing Gender    Team1
    B       Missing Gender                  Team1
    C       Missing Name                    Team2
    D       Missing Name                    Team2

    Team        Missing Gender      Missing Name
    Team1       2                   1
    Team2       0                   2

       SELECT
    "Team",
    sum(case when "DQ Info" like '%Missing Gender%' then 1 ELSE 0 END) as "Missing Gender",
    sum(case when "DQ Info" like '%Missing Name%' then 1 ELSE 0 END) as "Missing Name"
    FROM
    (*)
    GROUP BY "Team"

    Description                     Team1       Team2
    Missing Name; Missing Gender    1           0
    Missing Gender                  1           0
    Missing Name                    0           2

这不是我想要的。任何帮助都是非常感谢的，尽管我会继续修补，所以如果我能找到答案，我会更新这篇文章。请注意，这只是数据集的一个示例，而不是实际的数据集

编辑：根据bpgergo的建议进行以下查询。在阅读了一些内容之后，下面的代码似乎会短路，即一旦满足内部大小写中的第一个条件，就会终止查询，这意味着它将永远无法对一列进行多次计数。很遗憾，但我想我必须坚持我最初的质疑

    SELECT
    "Description",
    sum(case when "Team" like 'Team1' then 1 ELSE 0 END) as "Team1",
    sum(case when "Team" like 'Team2' then 1 ELSE 0 END) as "Team2"
    FROM(SELECT
    "Team",
    case when "DQ Info" like '%[Check Role]%' then '[Check Role]'
    ELSE case when "DQ Info" like '%[Client deceased]%' then '[Client deceased]'
    ELSE case when "DQ Info" like '%[2 Parents not recorded]%' then '[2 Parents not recorded]'
    ELSE case when "DQ Info" like '%[Religion not recorded]%' then '[Religion not recorded]'
    ELSE case when "DQ Info" like '%[1st Language not recorded]%' then '[1st Language not recorded]'
    ELSE case when "DQ Info" like '%[Ethnicity not recorded]%' then '[Ethnicity not recorded]'
    ELSE case when "DQ Info" like '%[No Current Worker]%' then '[No Current Worker]'
    ELSE case when "DQ Info" like '%[No Current Team]%' then '[No Current Team]'
    ELSE case when "DQ Info" like '%[Update Gender]%' then '[Update Gender]'
    ELSE case when "DQ Info" like '%[No Plan]%' then '[No Plan]'
    ELSE case when "DQ Info" like '%[Update Plan]%' then '[Update Plan]'
    END END END END END END END END END END END
     as "Description"
    FROM(
    *
    FROM
    (*)WORKLOAD)DATA)
    GROUP BY "Description"

---

你已经走到一半了。尝试这样做作为内部选择

select 
case when "Description" like '%Missing Gender%' then "Missing_gender" 
ELSE case when "Description" like '%Missing Name%' then "Missing_name" ELSE null END
END as "Description",
Team
from your_table

整个选择是这样的

SELECT
"Description",
sum(case when "Team" = 'Team1' then 1 ELSE 0 END) as "Team1",
sum(case when "Team" = 'Team2' then 1 ELSE 0 END) as "Team2",
FROM
(
  select 
  case when "Description" like '%Missing Gender%' then "Missing_gender" 
  ELSE case when "Description" like '%Missing Name%' then "Missing_name" ELSE null END
  END as "Description",
  Team
  from your_table
)
GROUP BY "Description"

---

谢谢-这很有道理。然而，当我运行查询时，它并没有返回所有的“描述”类别，计数也不完全正确。我认为当在内部查询中使用case时，它只是标识“Description”中的第一个错误——因此，如果一个ID有两个错误，那么上面的查询将只标识该查询中的第一个错误（希望这是有意义的！）。我已经发布了上述查询的缩写版本。