Sql '；没有单一的组功能'；在oracle中使用Listag时

我的查询正在使用Listag，它显示了一个错误00937。00000-“不是单个组功能” 我经历了许多类似于此错误的stackoverflow问题，这些答案使用了一些子查询来解决此问题。我不想在此查询中编写子查询

SELECT DISTINCT AMD.UNID AS APPLICATION_REF_ID, 
LISTAGG(LOC.PLT,',') WITHIN GROUP (ORDER BY LOC.PLT ) AS MYLOC  
FROM TAB1 AMD
LEFT JOIN TAB2 PER
ON NVL (AMD.PERMITNEWID, AMD.PERMITID) = PER.UNID
LEFT JOIN TAB3 LOC
ON NVL(AMD.PERMITNEWID, AMD.PERMITID) = LOC.PERMITID
WHERE NVL (AMD.PERMITNEWID, AMD.PERMITID) = PER.UNID

通过以下方式尝试分组：

SELECT amd.unid AS application_ref_id,
       LISTAGG (loc.plt, ',') WITHIN GROUP (ORDER BY loc.plt) AS myloc
  FROM tab1 amd
       LEFT JOIN tab2 per ON NVL (amd.permitnewid, amd.permitid) = per.unid
       LEFT JOIN tab3 loc
           ON NVL (amd.permitnewid, amd.permitid) = loc.permitid
 WHERE NVL (amd.permitnewid, amd.permitid) = per.unid
GROUP BY amd.unid

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您缺少一个

分组依据

，如果您是按

UNID进行分组

SELECT AMD.UNID AS APPLICATION_REF_ID, 
LISTAGG(LOC.PLT,',') WITHIN GROUP (ORDER BY LOC.PLT ) AS MYLOC  
FROM TAB1 AMD
LEFT JOIN TAB2 PER
ON NVL (AMD.PERMITNEWID, AMD.PERMITID) = PER.UNID
LEFT JOIN TAB3 LOC
ON NVL(AMD.PERMITNEWID, AMD.PERMITID) = LOC.PERMITID
WHERE NVL (AMD.PERMITNEWID, AMD.PERMITID) = PER.UNID
GROUP BY AMD.UNID

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这正在工作。谢谢，是否可以为聚合获取不同的LOC.PLT值？它给出了一个错误“字符串连接的结果太长”我的查询中有更多的join语句。您需要将其移动到子查询中，然后进行join