Sql 如何为具有特定值的重复id选择唯一id计数

例如，如果我有这张桌子

 report_date     id    customerCount    orderNr
  2020-02-20    123        12              10
  2020-02-19    123        18              11
  2020-02-18    123        0               12
  2020-02-20    321        0               0
  2020-02-19    321        0               0
  2020-02-18    321        0               0
  2020-02-20    456        17              13
  2020-02-19    456        0               0
  2020-02-18    456        15              14
  2020-02-20    654        0               0
  2020-02-19    654        0               0
  2020-02-18    654        0               0

我想选择其所有行均为customerCount=0和orderNr=0的id计数。要列出所有id，可以使用聚合和having。布尔聚合便于表达约束：

select id
from mytable
group by id
having bool_and(customerCount = 0) and bool_and(order_nr = 0)

如果要计算满足条件的ID数量，可以添加另一个聚合级别：

select count(*) cnt
from (
    select id
    from mytable
    group by id
    having bool_and(customerCount = 0) and bool_and(order_nr = 0)
) t

select count(*)
from (select id
      from t
      group by id
      having max(customerCount) = 0 and max(orderNr) = 0
     ) i;

---

一种方法使用两级聚合：

select count(*) cnt
from (
    select id
    from mytable
    group by id
    having bool_and(customerCount = 0) and bool_and(order_nr = 0)
) t

select count(*)
from (select id
      from t
      group by id
      having max(customerCount) = 0 and max(orderNr) = 0
     ) i;

注意：这假设值从来都不是负值，考虑到示例值和命名，这似乎很合理

另一种方法不存在：