Sql 如何根据Postgres中的固定时间间隔迭代表?
我想获得所有行,对于这些行,在给定的时间段内每48小时的间隔都满足以下条件。 每次它们都是真的,我就用一个值为1的标志来表示它 这就是我到目前为止所做的Sql 如何根据Postgres中的固定时间间隔迭代表?,sql,database,postgresql,plpgsql,Sql,Database,Postgresql,Plpgsql,我想获得所有行,对于这些行,在给定的时间段内每48小时的间隔都满足以下条件。 每次它们都是真的,我就用一个值为1的标志来表示它 这就是我到目前为止所做的 DO $$ DECLARE i record; CHARTTIME TIMESTAMP; BEGIN FOR i IN SELECT * FROM schema.lab L JOIN schema.icu I ON L.ID = I.ID WHERE L.ITEM = 50912 A
DO
$$
DECLARE
i record;
CHARTTIME TIMESTAMP;
BEGIN
FOR i IN SELECT * FROM schema.lab L
JOIN schema.icu I ON L.ID = I.ID
WHERE L.ITEM = 50912 AND
L.CHARTTIME < I.INTIME AND L.CHARTTIME > (I.INTIME - INTERVAL '7 DAY')
LOOP
CHARTTIME := L.CHARTTIME;
FOREACH CHARTTIME IN ARRAY CHARTTIME + INTERVAL '48 HOUR'
LOOP
IF L.VALUENUM > L.VALUENUM + 0.3 THEN
'1'::INTEGER AS FLAG
END IF;
END LOOP;
END LOOP;
END;
$$
;
下面是实现这些表的代码
CREATE TABLE SCHEMA.LAB (
ID_SUB INTEGER PRIMARY KEY,
ICU INTEGER NOT NULL,
ITEM INTEGER NOT NULL,
CHARTTIME TIMESTAMP NOT NULL,
VALUENUM DOUBLE PRECISION NOT NULL);
实验室的行数为:
ICU的行数为:
为了打印我想要的内容,我必须满足以下条件:
SCHEMA.LAB L在LAB.ICU=I.ID上加入SCHEMA.ICU I,并且该L.ITEM=50912和L.CHARTTIMELAB.ID_SUB, ICU.ID, LAB.ITEM, LAB.CHARTTIME, LAB.VALUENUM, ICU.INTIME FLAG
3, 3, 50912, 2020-07-18 20:03:00, 1, 2020-07-20 20:01:00 1
4, 4, 50912, 2020-07-20 17:17:00, 3.1, 2020-07-21 20:03:00. 1
这是一个试探性的回答。它确实需要更完整的数据来认真对待。下面是:
SELECT
*, 1 AS flag
FROM
(SELECT
*,
valuenum - LAG(valuenum, 1) OVER(partition by item) AS diff,
intime - LAG(intime, 1) OVER(partition by item) AS time_diff
FROM
lab L
JOIN
icu I
ON
L.id_sub = I.id
WHERE
L.item = 50912
AND
L.charttime < I.intime AND L.charttime > (I.intime - INTERVAL '7 DAY')
) AS select_diff
WHERE
select_diff.diff > 0.3
AND
select_diff.time_diff <interval '48 hours';
在数组CHARTTIME中,我没有看到FOREACH CHARTTIME中的任何数组。这是一个重复:@AdriankAver您建议如何迭代生成的行?@a_horse_和_no_名称我知道,这一个有更准确的解释。do函数无法返回任何内容,因此这是第一个问题,你想对结果做什么?
(1,1,50912,2020-07-17 20:48:00,0.7)
(2,2,50829,2020-07-17 20:48:00,1)
(3,3,50912,2020-07-18 20:03:00,1)
(4,4,50912,2020-07-20 17:17:00,3.1)
(1,1,73271,2020-05-17 17:58:00,0.2)
(2,2,50912,2020-07-17 21:41:00,1.7)
(1,2020-06-17 20:01:00,1)
(2,2020-07-15 00:48:00,2)
(3,2020-07-20 20:01:00,3)
(4,2020-07-21 20:03:00,4)
LAB.ID_SUB, ICU.ID, LAB.ITEM, LAB.CHARTTIME, LAB.VALUENUM, ICU.INTIME FLAG
3, 3, 50912, 2020-07-18 20:03:00, 1, 2020-07-20 20:01:00 1
4, 4, 50912, 2020-07-20 17:17:00, 3.1, 2020-07-21 20:03:00. 1
SELECT
*, 1 AS flag
FROM
(SELECT
*,
valuenum - LAG(valuenum, 1) OVER(partition by item) AS diff,
intime - LAG(intime, 1) OVER(partition by item) AS time_diff
FROM
lab L
JOIN
icu I
ON
L.id_sub = I.id
WHERE
L.item = 50912
AND
L.charttime < I.intime AND L.charttime > (I.intime - INTERVAL '7 DAY')
) AS select_diff
WHERE
select_diff.diff > 0.3
AND
select_diff.time_diff <interval '48 hours';