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Sql 如何在存储过程的IN筛选器中将nvarchar转换为int_Sql_Sql Server 2008_Stored Procedures - Fatal编程技术网

Sql 如何在存储过程的IN筛选器中将nvarchar转换为int

Sql 如何在存储过程的IN筛选器中将nvarchar转换为int,sql,sql-server-2008,stored-procedures,Sql,Sql Server 2008,Stored Procedures,我有一个存储过程来生成一个文本文件,其中有很多过滤器,这里就是 -- ============================================= -- Author: Ricardo Ríos -- Create date: 17/01/2014 -- Description: Genera el TXT para Importar a Saint -- ============================================= ALTER PROCED

我有一个存储过程来生成一个文本文件,其中有很多过滤器,这里就是

-- =============================================
-- Author:      Ricardo Ríos
-- Create date: 17/01/2014
-- Description: Genera el TXT para Importar a Saint
-- =============================================
ALTER PROCEDURE [dbo].[SP_SAINT_TXT]
    -- Add the parameters for the stored procedure here
        (   
        @nomina VARCHAR(MAX),
        @gerencia VARCHAR(MAX),
        @sucursal VARCHAR(MAX),
        @empresa VARCHAR(MAX),
        @departamento VARCHAR(MAX),
        @cargo VARCHAR(MAX),
        @horario VARCHAR(MAX),
        @locacion VARCHAR(MAX),
        @empleados VARCHAR(MAX),
        @desde DATETIME,
        @hasta DATETIME
        )
AS
BEGIN

SET NOCOUNT ON;

DECLARE @cedula varchar(max), @exnocturnas DECIMAL(5,2),
@diast DECIMAL(5,2), @diasf DECIMAL(5,0), @diasd DECIMAL(5,2),
@matut DECIMAL(5,2), @vespe DECIMAL(5,2), @noctu DECIMAL(5,2),
@linea varchar(max), @txt varchar(max),  
@l1 varchar(max),
@l2 varchar(max),
@l3 varchar(max),
@l4 varchar(max),
@l5 varchar(max),
@l6 varchar(max),
@l7 varchar(max)
SET @txt = ''

SET @nomina = (SELECT REPLACE(@nomina, '(', ''))
SET @nomina = (SELECT REPLACE(@nomina, ')', ''))
SET @gerencia = (SELECT REPLACE(@gerencia, '(', ''))
SET @gerencia = (SELECT REPLACE(@gerencia, ')', ''))
SET @sucursal = (SELECT REPLACE(@sucursal, '(', ''))
SET @sucursal = (SELECT REPLACE(@sucursal, ')', ''))
SET @empresa = (SELECT REPLACE(@empresa, '(', ''))
SET @empresa = (SELECT REPLACE(@empresa, ')', ''))
SET @departamento = (SELECT REPLACE(@departamento, '(', ''))
SET @departamento = (SELECT REPLACE(@departamento, ')', ''))
SET @cargo = (SELECT REPLACE(@cargo, '(', ''))
SET @cargo = (SELECT REPLACE(@cargo, ')', ''))
SET @locacion = (SELECT REPLACE(@locacion,'(',''))
SET @locacion = (SELECT REPLACE(@locacion,')',''))
SET @empleados = (SELECT REPLACE(@empleados,'(',''))
SET @empleados = (SELECT REPLACE(@empleados,')',''))

    declare cursor_txt cursor for
    SELECT B.ID AS cedula, 
    SUM(A.extrasnocturnas) AS extrasnocturnas, 
    SUM(A.diastrabajados) AS diastrabajados, 
    SUM(A.diasfaltantes) AS diasfaltantes, 
    SUM(A.diasdescanso) AS diasdescanso, 
    SUM(A.maturinas) AS maturinas, 
    SUM(A.vespertinas) AS vespertinas, 
    SUM(A.nocturnas) AS nocturnas
    FROM exsaint A
    RIGHT JOIN tabela B ON A.cedula = B.ID
    WHERE A.desde >= @desde AND A.hasta <= @hasta
    AND B.tipo_nomina IN (CASE WHEN @nomina = '-1' THEN B.tipo_nomina ELSE @nomina END)
    AND B.gerencia IN (CASE WHEN @gerencia = '-1' THEN B.gerencia ELSE @gerencia END)
    AND B.sucursal IN (CASE WHEN @sucursal = '-1' THEN B.sucursal ELSE @sucursal END)
    AND B.empresa IN (CASE WHEN @empresa = '-1' THEN B.empresa ELSE @empresa END)
    AND B.departamento IN (CASE WHEN @departamento = '-1' THEN B.departamento ELSE @departamento END)
    AND B.cargo IN (CASE WHEN @cargo = '-1' THEN B.cargo ELSE @cargo END)
    AND B.locacion IN (CASE WHEN @locacion = '-1' THEN B.locacion ELSE @locacion END)
    AND B.ID IN (CASE WHEN @empleados = '-1'THEN B.ID ELSE @empleados END)
    GROUP BY ID
    ORDER BY ID
    open cursor_txt
        fetch next from cursor_txt into @cedula, @exnocturnas, @diast, @diasf, @diasd, @matut, @vespe, @noctu

        while @@fetch_status = 0
        begin
            SET @linea = ''
            SET @l1 = CAST(@exnocturnas AS CHAR(8))
            SET @l2 = CAST(@diast AS CHAR(8))
            SET @l3 = CAST(@diasf AS CHAR(3))
            SET @l4 = CAST(@diasd AS CHAR(8))
            SET @l5 = CAST(@matut AS CHAR(8))
            SET @l6 = CAST(@vespe AS CHAR(8))
            SET @l7 = CAST(@noctu AS CHAR(8))
            SET @linea = 
                LTRIM(CONVERT(CHAR(16),@cedula)) +  
                LTRIM(RTRIM((SELECT CONVERT(VARCHAR(10), @hasta, 103) AS [DD/MM/YYYY]))) + 
                LTRIM(RTRIM('000')) + 
                LTRIM(RTRIM(REPLICATE('0', 8-LEN(@l1)) + @l1 )) +
                LTRIM(RTRIM(REPLICATE('0', 8-LEN(@l2)) + @l2 )) +
                LTRIM(RTRIM(REPLICATE('0', 3-LEN(@l3)) + @l3 )) + 
                LTRIM(RTRIM(REPLICATE('0', 8-LEN(@l4)) + @l4 )) +
                LTRIM(RTRIM(REPLICATE('0', 8-LEN(@l5)) + @l5 )) +
                LTRIM(RTRIM(REPLICATE('0', 8-LEN(@l6)) + @l6 )) +
                LTRIM(RTRIM(REPLICATE('0', 8-LEN(@l7)) + @l7 )) +
                LTRIM(RTRIM('00000000')) +
                + CHAR(13) + CHAR(10);
            PRINT @txt
            PRINT @linea
            SET @txt = @txt + @linea
            fetch next from cursor_txt into @cedula, @exnocturnas, @diast, @diasf, @diasd, @matut, @vespe, @noctu
        end
    close cursor_txt
    deallocate cursor_txt

    SELECT @txt

END

有没有一种方法可以通过一些转换或其他方式添加这些过滤器,然后它就可以工作了?

啊,问题是它将其视为一个varchar,而不是一个整数

您需要做的是将它们拆分成另一个表或XML。这里最好解释一下:

编辑:只有链接的答案是错误的,因此我使用的方法是(从该链接):

Declare@Ids varchar(50)
设置@Ids='1,2,3,5,4,6,7,98234'
声明@XML
将@XML=CAST(''+REPLACE(@Ids,'','')+''设置为XML)
选择*
从…起
有点
内部连接@XML.nodes('i')x(i)
在SomeTable.Id=x.i.value(‘.’,‘VARCHAR(MAX)’)上

CASE

否则,您可以尝试为此任务实施一些可能的解决方法。这个是基于。更改SQL的这一部分..:

AND B.empresa IN (CASE WHEN @empresa = '-1' THEN B.empresa ELSE @empresa END)
……为此:

AND (
     @empresa = '-1' 
        or 
     B.empresa IN (SELECT t.id.value('.', 'int') id FROM @empresaXml.nodes('//s') as t(id))
    )
@empresa='-1'
时,上述语句的计算结果总是
True
。否则,
int
值将从
@empresaXml
变量中提取,并将用于筛选列
empresa

变量
@empresaXml
自声明并填充如下:

DECLARE @empresaXml XML
SET @empresaXml = CAST('<s>' + REPLACE(@empresa, ',', '</s><s>') + '</s>' AS XML)

我可以用一个分割函数来完成这项工作

我在这里使用Jeff Moden 2012年在SQLServerCentral上发布的DelimitedSplit8k函数:

您可以将该函数添加到数据库(本文中的第三个代码框到最后一个代码框),然后按如下方式调用它:

 AND B.empresa IN (CASE WHEN @empresa = '-1' THEN B.empresa ELSE (SELECT split.item from DelimitedSplit8k(@empresa,',') split) END)

列tabela.empresa的数据类型是什么?都是整数,只是desde和hasta是datetime,问题是我希望保留类似于empresa在(2,3,5)侧边中的位置注意:您不应该在存储过程中使用
sp
前缀。微软已经这样做了,而且你确实有可能在将来的某个时候发生名称冲突。最好只是简单地避免使用
sp.
并使用其他东西作为前缀,或者根本不使用前缀!考虑使用而不是解析<代码> VARCHAR < /Cord>参数。我认为这不是修复这些问题的最佳方法,因为我有几个过滤器,也尝试了提供的链接,仍然没有成功地建议使用<代码>选项(重新编译)< /C> >,如您所讨论的,您将得到我的赞成。我现在得到这个奇怪的错误-> MSG 1934,级别16,状态1,程序SP_SAINT_TXT,第64行选择失败,因为以下设置选项的设置不正确:“数值\u ROUNDABORT”。验证集合选项是否正确用于索引视图和/或计算列上的索引和/或筛选索引和/或查询通知和/或XML数据类型方法和/或空间索引操作。@RicardoRios第64行中的内容,
选择B.ID作为cedula,
?首先尝试不使用
选项(重新编译)
(如果您正在使用它)。您用于测试的值是什么,
”(5,4)
?我正在使用这个->执行SP_SAINT_TXT'(4,1,2,3,6)'、'-1'、'(5,6,1,4,3,2)'、'-1'、'-1'、'-1'、'20140801'、'20150805'进行测试,看起来第64行是这一组@xmlclocacion=CAST('+REPLACE(@locacion'、'、'')+)@里卡多里奥斯一世用这个参数。错误消息显示
第64行选择失败…
,如果您发现第64行没有任何
选择
,则会很奇怪。无论如何,如果我不能重现错误,就很难诊断
DECLARE @empresaXml XML
SET @empresaXml = CAST('<s>' + REPLACE(@empresa, ',', '</s><s>') + '</s>' AS XML)
CREATE TABLE MyTable(empresa int, data varchar(10))
;

INSERT INTO MyTable
VALUES
  (1,'a'),
  (2,'b'),
  (3,'c'),
  (4,'d'),
  (5,'e')
;

Declare @empresa varchar(50) = '( 5 , 4 )'
DECLARE @empresaXml XML

SET @empresa = REPLACE(REPLACE(@empresa,'(',''), ')', '')
SET @empresaXml = CAST('<s>' + REPLACE(@empresa, ',', '</s><s>') + '</s>' AS XML)

SELECT *
FROM MyTable B
WHERE (@empresa = '-1' or B.empresa IN (SELECT t.id.value('.', 'int') id
                          FROM @empresaXml.nodes('//s') as t(id)))
| empresa | data |
|---------|------|
|       4 |    d |
|       5 |    e |
 AND B.empresa IN (CASE WHEN @empresa = '-1' THEN B.empresa ELSE (SELECT split.item from DelimitedSplit8k(@empresa,',') split) END)