Sql 您如何从两个不同的公司中选择前五名？

我试图做这个1SQL语句，其中第一个1的公司编号是1，第二个是2

理想的结果是从每家公司中选出最优秀的销售人员，在本例中有2家公司，但我需要一个查询，根据公司数量（1,2,3）得出结果（5,10,15）

** 从第一个到第二个**

Total Deals First      Last
1           MARK       O'DELL
1           Edward     Thatch
1           FranK      Cavelier
1           Chris      Fluffer
1           Chris      Farley

---

首先，可以简化每个子查询：

  SELECT COUNT(d.DealNumber) AS Deals, e.FirstName AS First,
         e.LastName AS Last, e.EntityNumber
  FROM DealEmployee de INNER JOIN
       Entity e
       ON de.EmployeeID = e.EntityID RIGHT OUTER JOIN
       Deal d
       ON de.DealID = d.DealID
  WHERE d.PurchaseDate >= '2014-01-01' AND 
        d.PurchaseDate <= '2014-11-01' AND 
        d.CompanyNumber = '1' AND d.Status = 2 AND de.Type = 'Salesperson'
  GROUP BY e.FirstName, e.LastName, e.EntityNumber
  ORDER BY TotalDeals DESC;

SELECT t.*
FROM (SELECT COUNT(d.DealNumber) AS Deals, e.FirstName AS First,
             e.LastName AS Last, e.EntityNumber,
             ROW_NUMBER() OVER (PARTITION BY e.FirstName, e.LastName, e.EntityNumber
                                ORDER BY COUNT(d.DealNumber) DESC) as seqnum
      FROM DealEmployee de INNER JOIN
           Entity e
           ON de.EmployeeID = e.EntityID RIGHT OUTER JOIN
           Deal d
           ON de.DealID = d.DealID
      WHERE d.PurchaseDate >= '2014-01-01' AND 
            d.PurchaseDate <= '2014-11-01 00:00:00' AND 
            d.CompanyNumber = '1' AND d.Status = 2 AND de.Type = 'Salesperson'
      GROUP BY e.FirstName, e.LastName, e.EntityNumber
     ) t
WHERE seqnum <= 5
ORDER BY TotalDeals DESC;

---

你希望结果中有多少条记录：5条（两家公司加起来）或10条（每家公司5条）？每个公司5条，但如果能在超过2家公司的情况下工作就好了。请用样本数据和期望的结果编辑你的问题。好的，我做了，希望答案是显示每个公司的前5名销售经理，但在这种情况下，有多个公司。我会将公司编号设为变量吗？这有可能吗？这会带来59笔交易，而我只想让每家公司得到5笔。您还可以帮助我理解Seqnum、T.*和分区的含义吗？Seqnum变量应该是销售人员的计数吗？因为它为59个变量中的每一个返回1rows@Learningyouslowly . . . 关键是

partitionby

子句，但我不确定哪个是正确的。从您的文本来看，它似乎是按公司编号划分的，但该字段不起作用。它必须是

分组依据

字段之一。您有什么建议？

  SELECT COUNT(d.DealNumber) AS Deals, e.FirstName AS First,
         e.LastName AS Last, e.EntityNumber
  FROM DealEmployee de INNER JOIN
       Entity e
       ON de.EmployeeID = e.EntityID RIGHT OUTER JOIN
       Deal d
       ON de.DealID = d.DealID
  WHERE d.PurchaseDate >= '2014-01-01' AND 
        d.PurchaseDate <= '2014-11-01' AND 
        d.CompanyNumber = '1' AND d.Status = 2 AND de.Type = 'Salesperson'
  GROUP BY e.FirstName, e.LastName, e.EntityNumber
  ORDER BY TotalDeals DESC;

SELECT t.*
FROM (SELECT COUNT(d.DealNumber) AS Deals, e.FirstName AS First,
             e.LastName AS Last, e.EntityNumber,
             ROW_NUMBER() OVER (PARTITION BY e.FirstName, e.LastName, e.EntityNumber
                                ORDER BY COUNT(d.DealNumber) DESC) as seqnum
      FROM DealEmployee de INNER JOIN
           Entity e
           ON de.EmployeeID = e.EntityID RIGHT OUTER JOIN
           Deal d
           ON de.DealID = d.DealID
      WHERE d.PurchaseDate >= '2014-01-01' AND 
            d.PurchaseDate <= '2014-11-01 00:00:00' AND 
            d.CompanyNumber = '1' AND d.Status = 2 AND de.Type = 'Salesperson'
      GROUP BY e.FirstName, e.LastName, e.EntityNumber
     ) t
WHERE seqnum <= 5
ORDER BY TotalDeals DESC;