Sql 子查询Bigquery上的分组依据和平均值

我试图按日期对记录进行分组，并针对特定的一天，获取其中一列（称为延迟）的平均值。我有以下标准SQL查询，当我尝试获取表的平均值和分组依据时，它可以工作，但不能工作：

SELECT * 
From 
(
SELECT 'ADS-B Average Latency for Asia' as metric_name, 'Daily' as metric_period_type,
  DATE(timestamp) as metric_date, collection_type, UNIX_SECONDS(ingestion_time) - UNIX_SECONDS(timestamp) as latency
  FROM `analytics.aoi_table` a
  order by metric_date
) table 

这是表格：

当我尝试使用下面的sql执行上表的avg和group by时，我得到了以下错误：语法错误：Expected“），但在[10:3]处得到了关键字group

导致错误的SQL语句：

#standardSQL

SELECT * 
From 
(
SELECT 'ADS-B Average Latency for Asia' as metric_name,
  DATE(timestamp) as metric_date, collection_type, AVG(UNIX_SECONDS(ingestion_time) - UNIX_SECONDS(timestamp)) as latency
  FROM `ais-data-analysis.customer_analytics.itochu_aoi_table` a
  order by metric_date
  group by metric_date, collection_type
) table 

---

您的

分组依据

和

排序依据

顺序不正确。此外，您不需要子查询：

select 'ADS-B Average Latency for Asia' as metric_name,
       DATE(timestamp) as metric_date, collection_type, AVG(UNIX_SECONDS(ingestion_time) - UNIX_SECONDS(timestamp)) as latency
from `ais-data-analysis.customer_analytics.itochu_aoi_table` a
group by metric_date, collection_type
order by metric_date

---

orderby

子句位于

groupby

子句之后。此外，无需包装查询，您只需执行以下操作：

SELECT 
    'ADS-B Average Latency for Asia' as metric_name,
    DATE(timestamp) as metric_date, 
    collection_type, 
    AVG(UNIX_SECONDS(ingestion_time) - UNIX_SECONDS(timestamp)) as latency
FROM `ais-data-analysis.customer_analytics.itochu_aoi_table` a
GROUP BY metric_date, collection_type
ORDER BY metric_date, collection_type