如何对两个复杂的SQL查询执行外部联接？

我有两个相对复杂的查询，我正试图将它们合并到一个结果集中

结果集1：

SELECT  sq.question_id,     
    COUNT(ra.question_option_id) AS TotalAnswers

FROM    dbo.survey_question sq
    LEFT OUTER JOIN dbo.question_option qo
        ON sq.question_id = qo.question_id
    LEFT OUTER JOIN dbo.form_response_answers ra
        ON qo.question_option_id = ra.question_option_id
GROUP BY sq.question_id

结果集2：

SELECT  p.program_id, 
    p.pre_survey_form_id, 
    p.post_survey_form_id, 
    fq.form_id, 
    sq.question_id, 
    sq.question_text, 
    qo.question_option_id, 
    qo.option_text, 
    G.Total

FROM    dbo.program p
    LEFT OUTER JOIN dbo.form_question fq
        ON p.pre_survey_form_id = fq.form_id OR p.post_survey_form_id = fq.form_id
    LEFT OUTER JOIN dbo.survey_question sq
        ON fq.question_id = sq.question_id
    LEFT OUTER JOIN dbo.question_option qo 
        ON sq.question_id = qo.question_id
    LEFT OUTER JOIN (
        SELECT ra.question_id, ra.question_option_id, COUNT(*) AS Total
        FROM dbo.form_response_answers ra
        GROUP BY ra.question_option_id, ra.question_id 
    ) G
        ON G.question_id = sq.question_id AND G.question_option_id = qo.question_option_id

ORDER BY p.program_id, fq.form_id, sq.question_id, qo.question_option_id

---

我需要在问题id匹配的行上加入它们。请提供帮助。

第一个查询中第二个查询中缺少的唯一附加信息是

COUNT(ra.question_option_id) AS TotalAnswers

在

dbo.form\u response\u回答ra

表中

因此，只需将此计数添加到您的选择中：

    (select count(*) from dbo.form_response_answers ra
         where qo.question_option_id = ra.question_option_id) as AS TotalAnswers

例如：

SELECT  p.program_id, 
        p.pre_survey_form_id, 
        p.post_survey_form_id, 
        fq.form_id, 
        sq.question_id, 
        sq.question_text, 
        qo.question_option_id, 
        qo.option_text, 
        G.Total,
        (select count(*) from dbo.form_response_answers ra
         where qo.question_option_id = ra.question_option_id) as AS TotalAnswers


FROM    dbo.program p
    LEFT OUTER JOIN dbo.form_question fq
    ON p.pre_survey_form_id = fq.form_id OR p.post_survey_form_id = fq.form_id
LEFT OUTER JOIN dbo.survey_question sq
    ON fq.question_id = sq.question_id
LEFT OUTER JOIN dbo.question_option qo 
    ON sq.question_id = qo.question_id
LEFT OUTER JOIN (
    SELECT ra.question_id, ra.question_option_id, COUNT(*) AS Total
    FROM dbo.form_response_answers ra
    GROUP BY ra.question_option_id, ra.question_id 
) G
    ON G.question_id = sq.question_id AND G.question_option_id = qo.question_option_id

ORDER BY p.program_id, fq.form_id, sq.question_id, qo.question_option_id

---

编辑：您需要每个sq问题id的总答案

因此，我应该插入：

(select count(ra2.question_option_id) 
   from dbo.question_option qo2
   LEFT OUTER JOIN dbo.form_response_answers ra2
       ON qo2.question_option_id = ra2.question_option_id
   where qo2.question_id = sq.question_id) as TotalAnswers

---

当然，现在会重复多次，因为查询2中的行比查询1中的行多。

我不是专家，但不会：

SELECT  sq.question_id,     
    COUNT(ra.question_option_id) AS TotalAnswers INTO [#temp_table1]
...

SELECT  p.program_id, 
    p.pre_survey_form_id, 
    p.post_survey_form_id, 
    fq.form_id, 
    sq.question_id, 
    sq.question_text, 
    qo.question_option_id, 
    qo.option_text, 
    G.Total
INTO [#temp_table2]
...

然后：

SELECT * FROM [#temp_table1] JOIN ON [#temp_table1].question_id = [#temp_table2].question_id

---

完成工作？

您是否尝试过使用CTE或表格变量？好的，我尝试过使用CTE，但没有任何运气。我能够创建一个CTE，但它不允许我做两个。我仍然不知道如何以这种方式实现JOIN。如何处理表变量？这不起作用，因为它会丢失我在第一个查询中的分组，因此计数会返回不同的结果。实际上，重复此操作是可取的，因为我将使用该列计算选择特定响应的次数的百分比。