Oracle SQL-基于concat的外部联接
我需要交叉连接两个表,但连接条件为:Oracle SQL-基于concat的外部联接,sql,oracle,join,outer-join,Sql,Oracle,Join,Outer Join,我需要交叉连接两个表,但连接条件为: Select FutureInventory.Item, To_Number(Concat(Location, Channel_Id)) Location, From V_CUST_FUTURE_INV_POSITION FutureInventory, xx_Item_Loc_Info_V ItemLoc Where FutureInventory.Item(+) = ItemLoc.Item And
Select FutureInventory.Item,
To_Number(Concat(Location, Channel_Id)) Location,
From V_CUST_FUTURE_INV_POSITION FutureInventory,
xx_Item_Loc_Info_V ItemLoc
Where FutureInventory.Item(+) = ItemLoc.Item
And To_Number(Concat(Location, Channel_Id))(+) = ItemLoc.Loc;
我想用ItemLoc.Loc将列外部连接到_编号(Concat(位置,通道_Id))
在Oracle中,如果要放置(+)符号进行外部联接,可以使用适当的
join
类型,就像在所有其他数据库中一样。我认为你想要的逻辑是:
select FutureInventory.Item,
To_Number(Concat(Location, Channel_Id)) as Location,
from xx_Item_Loc_Info_V ItemLoc LEFT JOIN
V_CUST_FUTURE_INV_POSITION FutureInventory,
on FutureInventory.Item = ItemLoc.Item AND
To_Number(Concat(Location, Channel_Id)) = ItemLoc.Loc;
首先,使用显式连接语法-旧的
(+)
很难阅读,也很容易出错。第二,使用|
操作符而不是CONCAT
函数-同样,更易于阅读。因此,我们以
Select FutureInventory.Item,
To_Number(Location || Channel_Id) Location,
From xx_Item_Loc_Info_V ItemLoc
LEFT OUTER JOIN V_CUST_FUTURE_INV_POSITION FutureInventory,
ON FutureInventory.Item = ItemLoc.Item And
To_Number(Location || Channel_Id) = ItemLoc.Loc
样本数据、期望的结果以及对逻辑的清晰解释都会有所帮助。