sqlserver2008中的Pivot函数

如何实现枢轴功能

我有一张数据表

Day     Period  subject  fromtime  totime

 ---------------------------------------------- 
Monday  1st   English   9:30    10:15

Monday  1st   English   9:30    10:15

Monday  5th   English   1:30    2:20 

Monday  8th   English   3:40    4:30

但我需要的格式

day     period(1st)     2nd    3rd...... 5th...          8th

--------------------------------------------------------------------------
Monday    1st           nill    nill     5th             8th
        english                        english        english

Tuesday .......

就这样

如何执行pivot函数以获取此格式

请帮帮我

我已经使用了我的查询

SELECT DAY, [1st],[2nd],[3rd],[4th], [5th],[6th],[7th], [8th]
FROM 
    (
        SELECT Day, Period, Subject,FromTime,ToTime
        FROM StaffTimeTableEntry
    ) up
PIVOT (Min(Subject) FOR Period IN ([1st],[2nd],[3rd],[4th], [5th],[6th],[7th], [8th])) AS pvt
order by Day

结果是

day        1st     2nd      3rd     4th    5th     6th     7th    8th

----------------------------------------------------------------------------------
Friday  NULL    NULL    NULL    NULL    NULL    NULL    English NULL

Monday  NULL    NULL    NULL    NULL    English NULL    NULL    NULL

Monday  NULL    NULL    NULL    NULL    NULL    NULL    NULL    English

Monday  English NULL    NULL    NULL    NULL    NULL    NULL    NULL

Saturday    NULL    NULL    NULL    NULL    NULL    English NULL

Thursday    NULL    NULL    NULL    English NULL    NULL    NULL

Tuesday NULL    English NULL    NULL    NULL    NULL    NULL    NULL

Tuesday NULL    NULL    NULL    NULL    NULL    English NULL    NULL

Wednesday   NULL    NULL    NULL    NULL    NULL    English NULL    

但这里我也有3张周一的唱片，而不是一张周一的唱片

如何在一天内获得一条记录…？

试试以下方法：

SELECT DAY, [1st],[2nd],[3rd],[4th], [5th],[6th],[7th], [8th]
FROM 
    (
        SELECT Day, Period, Subject --,FromTime,ToTime
        FROM StaffTimeTableEntry
    ) up
PIVOT (Min(Subject) FOR Period IN ([1st],[2nd],[3rd],[4th], [5th],[6th],[7th], [8th])) AS pvt
order by Day

---

PIVOT运算符未“使用”的任何列将保留在最终结果集中，增加基数。

但这一天是以这种形式出现的，周五周一周六周四周三，但我需要按天排序。

按案例日期排序，当“周一”时，然后按1当“周二”，然后按2等。或者找到某种方法将一天转换为日期，然后按日期排序。