Sql 从like case语句派生的值的组计数

我有一个表格，表格中有格式的数据

PropertyValue字符串

用户签名www.website.com.brxxx/sales/selled

www.website.com用户/已售出

www.website.com.co.uk\暂挂销售税

我需要做的是根据下面sql中的site列进行分组，以获得每个站点的总数

SELECT top 1000
      CASE
            WHEN  propertyvaluestrings LIKE '%www.website.co.uk%' THEN 'UK'
            WHEN  propertyvaluestrings LIKE '%www.website.us%' THEN 'USA'
            WHEN  propertyvaluestrings LIKE '%www.website.com.br%' THEN 'Brazil'
            WHEN  propertyvaluestrings LIKE '%www.website.co.id%' THEN 'indonesia'
            WHEN  propertyvaluestrings LIKE '%www.website.com%' THEN 'Global'
       ELSE 'XXXXXXXXXXXXXXXX----Unknown'
       END as Site
    ,
    PropertyValueStrings

FROM profiles

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你的意思是计算每个国家的PropertyValue字符串的数量吗？如果是这样，这应该是可行的：

SELECT Site, COUNT(*) AS Count
FROM (
    SELECT (CASE
                WHEN  propertyvaluestrings LIKE '%www.website.co.uk%' THEN 'UK'
                WHEN  propertyvaluestrings LIKE '%www.website.us%' THEN 'USA'
                WHEN  propertyvaluestrings LIKE '%www.website.com.br%' THEN 'Brazil'
                WHEN  propertyvaluestrings LIKE '%www.website.co.id%' THEN 'indonesia'
                WHEN  propertyvaluestrings LIKE '%www.website.com%' THEN 'Global'
           ELSE 'XXXXXXXXXXXXXXXX----Unknown'
           END) AS [Site]
    ,
    propertyvaluestrings 
    FROM Profiles
) X
GROUP BY Site