Sql 记录两次之间的间隔

下面给出的是我所拥有的其中一个表中的一组数据，有没有办法跟踪空闲时间？e、 g 11:00-12:00和18:45-19:15作为该日期的间隔

       Date           Activity  From     To    Duration
2013-09-09 00:00:00.000 Work    08:00   11:00   3.00
2013-09-09 00:00:00.000 Travel  12:00   13:00   1.00
2013-09-09 00:00:00.000 Work    13:00   15:00   2.00
2013-09-09 00:00:00.000 Work    15:00   18:00   3.00
2013-09-09 00:00:00.000 Travel  18:00   18:45   0.75
2013-09-09 00:00:00.000 Work    19:15   22:15   3.00

我期待着下面这样的事情

       Date           Activity  From     To    Duration
2013-09-09 00:00:00.000 Work    08:00   11:00   3.00
2013-09-09 00:00:00.000 Gap     11:00   12:00   1.00
2013-09-09 00:00:00.000 Travel  12:00   13:00   1.00
2013-09-09 00:00:00.000 Work    13:00   15:00   2.00
2013-09-09 00:00:00.000 Work    15:00   18:00   3.00
2013-09-09 00:00:00.000 Travel  18:00   18:45   0.75
2013-09-09 00:00:00.000 Gap     18:45   19:15   0.50
2013-09-09 00:00:00.000 Work    19:15   22:15   3.00

这可以不循环地完成吗？如果是的话，？怎么做呢？

为什么DUARTION是INT类型？ 以下查询将原始表与输出间隙的查询合并，然后按日期和起始日期对该合并进行排序

请尝试：

select
    [Date],
    Activity,
    [From],
    [To],
    CONVERT(varchar(5), CONVERT(Datetime,[TO])-CONVERT(Datetime,[FROM]), 108) Duration
From
(
    select 
        [Date],
        'Gap' Activity,
        [To] [From],
        (select top 1 d.[From] from YourTable d where CONVERT(datetime, d.[Date]+d.[From])>CONVERT(datetime, a.[Date]+a.[To]) order by CONVERT(datetime, d.[Date]+d.[From])) as [To],
        NULL as Duration
    from YourTable a
    where 
        (select COUNT(*) from YourTable b where CONVERT(datetime, b.[Date]+b.[From])=CONVERT(datetime, a.[Date]+a.[To]))=0

    union all

    select * From YourTable
)x 
where 
    [To] IS NOT NULL
order by CONVERT(datetime, x.[Date]+x.[From])

---

请看这个。Alex输出应该是什么？@techdo:请在上面找到修改后的问题From和To列的数据类型是什么？您可以使用如下方法：选择ID，StartSeqNo=SeqNo+1，EndSeqNo=从dbo.GapsIslands中选择MINB.SeqNo作为B，其中B.ID=A.ID，从dbo.GapsIslands中选择B.SeqNo>A.SeqNo-1作为A，其中不存在，从dbo.GapsIslands中选择*作为B，其中B.ID=A.ID和B.SeqNo=A.SeqNo+1和SeqNo<从dbo.GapsIslands中选择MAXSeqNo，其中B.ID=A.ID，从本作品下面的链接。谢谢但是，当表中有大量数据时，它肯定会影响性能。有轻松的机会吗？

select
    [Date],
    Activity,
    [From],
    [To],
    CONVERT(varchar(5), CONVERT(Datetime,[TO])-CONVERT(Datetime,[FROM]), 108) Duration
From
(
    select 
        [Date],
        'Gap' Activity,
        [To] [From],
        (select top 1 d.[From] from YourTable d where CONVERT(datetime, d.[Date]+d.[From])>CONVERT(datetime, a.[Date]+a.[To]) order by CONVERT(datetime, d.[Date]+d.[From])) as [To],
        NULL as Duration
    from YourTable a
    where 
        (select COUNT(*) from YourTable b where CONVERT(datetime, b.[Date]+b.[From])=CONVERT(datetime, a.[Date]+a.[To]))=0

    union all

    select * From YourTable
)x 
where 
    [To] IS NOT NULL
order by CONVERT(datetime, x.[Date]+x.[From])