如何确定SQL中每个类别的最大值？

我的表格有如下记录：

ID          EmpID           EffectiveDate     PayElement  Amount   ComputeType      AddDeduction
    42  ISIPL001    2010-04-16 00:00:00.000 Basic     8000.00   On Attendance   Addition
    43  ISIPL001    2010-04-01 00:00:00.000 Con       2000.00   On Attendance   Addition
    44  ISIPL001    2010-04-01 00:00:00.000 HRA       2000.00   On Attendance   Addition
    54  ISIPL001    2011-01-01 00:00:00.000 Basic    15000.00   On Attendance   Addition
    55  ISIPL001    2011-01-01 00:00:00.000 Con       6000.00   On Attendance   Addition
    57  ISIPL001    2011-01-01 00:00:00.000 HRA       6000.00   On Attendance   Addition
    61  ISIPL001    2010-07-10 00:00:00.000 Basic    12000.00   On Attendance   Addition
    66  ISIPL001    2010-07-10 00:00:00.000 HRA       4200.00   On Attendance   Addition
    68  ISIPL001    2010-07-10 00:00:00.000 Con       5600.00   On Attendance   Addition

我希望结果显示如下：

i、 e对于我数据库中可用的每个支付要素，我需要记录每个支付要素的最长日期

因此，我的输出应该如下所示：

54  Basic 15000
55  Con    6000
57  HRA    6000

试试这个：

SELECT  ID, 
        PayElement, 
        Amount
  FROM  (
        SELECT a.*,
             RANK() OVER(PARTITION BY PayElement ORDER BY EffectiveDate DESC) AS rn
        FROM <YOUR_TABLE> a 
        )   a
WHERE rn = 1                

试试这个：

SELECT  ID, 
        PayElement, 
        Amount
  FROM  (
        SELECT a.*,
             RANK() OVER(PARTITION BY PayElement ORDER BY EffectiveDate DESC) AS rn
        FROM <YOUR_TABLE> a 
        )   a
WHERE rn = 1                

试试这个

select
  T.ID,
  T.PayElement,
  T.Amount
from
  Test T inner join (select MAX(T_DATE.EffectiveDate) as MAX_DATE, T_DATE.PayElement from Test T_DATE group by T_DATE.PayElement) T_DATE on (T.PayElement = T_DATE.PayElement) and (T.EffectiveDate = T_DATE.MAX_DATE)
order by
  T.ID

试试这个

select
  T.ID,
  T.PayElement,
  T.Amount
from
  Test T inner join (select MAX(T_DATE.EffectiveDate) as MAX_DATE, T_DATE.PayElement from Test T_DATE group by T_DATE.PayElement) T_DATE on (T.PayElement = T_DATE.PayElement) and (T.EffectiveDate = T_DATE.MAX_DATE)
order by
  T.ID

试试像这样的东西

Select 
   a.ID, a.PayElement, a.Amount 
From MyTable a
Inner Join (
   Select PayElement, max(EffectiveDate) as MaxDate From MyTable Group By PayElement
) sub on a.EffectiveDate = sub.MaxDate and a.PayElement = sub.PayElement

试试像这样的东西

Select 
   a.ID, a.PayElement, a.Amount 
From MyTable a
Inner Join (
   Select PayElement, max(EffectiveDate) as MaxDate From MyTable Group By PayElement
) sub on a.EffectiveDate = sub.MaxDate and a.PayElement = sub.PayElement