Sql 在外部联接中使用“选择零件”
这是我的SQL查询:Sql 在外部联接中使用“选择零件”,sql,stored-procedures,outer-join,Sql,Stored Procedures,Outer Join,这是我的SQL查询: SELECT b.MaakArtikel, b.Bewerking, [pp].dbo.WORKINGDAYADD('2013-06-27 00:00:00.000',0-b.Startdag_backwards) AS Startdatum, i.Class_06 AS Afdeling, b.Minuten*10+ISNULL(br.Tijd,0) AS Minuten, 1+ISNULL(br.Orders,0
SELECT
b.MaakArtikel,
b.Bewerking,
[pp].dbo.WORKINGDAYADD('2013-06-27 00:00:00.000',0-b.Startdag_backwards) AS Startdatum,
i.Class_06 AS Afdeling,
b.Minuten*10+ISNULL(br.Tijd,0) AS Minuten,
1+ISNULL(br.Orders,0) AS Aantal
FROM [pp].dbo.VW_BEWERKINGSTRUCTUUR b
LEFT OUTER JOIN [211].dbo.Items i
ON b.MaakArtikel = i.ItemCode
LEFT OUTER JOIN [pp].dbo.VW_BEZETTING_RAW br
ON [pp].dbo.WORKINGDAYADD('2013-06-27 00:00:00.000',0-b.Startdag_backwards) = br.Start
AND i.Class_06 = br.Afdeling
WHERE MaakArtikel = 'HT 10.038'
查询工作正常,但有点慢。那是因为我的第二个外部连接。我必须通过Startdatum
(在第4行选择)加入视图。由于它不是真实的列名,我不能在我的外部联接中直接使用它。这意味着函数[pp].dbo.WORKINGDAYADD()
必须触发两次(一次在我的选择中,这不是问题,一次在我的外部联接中,这是双重工作)
我可以编写一个存储过程,并在变量中使用函数[pp].dbo.WORKINGDAYADD()
的结果,但这是不可重复的。在我的外部联接
表达式中是否有使用Startdatum的方法?或者我真的必须为此使用存储过程吗?如何存储您的结果
[pp].dbo.WORKINGDAYADD('2013-06-27 00:00:00.000',0-Startdag_backwards) AS Startdatum
转换为SQL变量
DECLARE @myVariable DATETIME
SET @myVariable = [pp].dbo.WORKINGDAYADD('2013-06-27 00:00:00.000',0-Startdag_backwards)
然后在你的外连接上做这个
ON @myVariable = br.Start
或者类似的东西。
Bobby您可以将[pp].dbo.WORKINGDAYADD()
的输出存储在变量中,然后在代码中使用该变量。
(我假设函数的结果数据类型为datetime.)
您可以将函数移动到子查询,如下所示:
SELECT MaakArtikel,
Bewerking,
b.Startdatum,
i.Class_06 AS Afdeling,
Minuten * 10 + ISNULL(br.Tijd,0) AS Minuten,
1 + ISNULL(br.Orders, 0) AS Aantal
FROM ( SELECT *,
StartDatum = [pp].dbo.WORKINGDAYADD('2013-06-27 00:00:00.000', 0 - Startdag_backwards)
FROM [pp].dbo.VW_BEWERKINGSTRUCTUUR b
) b
LEFT OUTER JOIN [211].dbo.Items i
ON b.MaakArtikel = i.ItemCode
LEFT OUTER JOIN [pp].dbo.VW_BEZETTING_RAW br
ON b.Startdatum = br.Start
AND i.Class_06 = br.Afdeling
WHERE MaakArtikel = 'HT 10.038';
注意
我不允许使用SELECT*
,在您的工作查询中,您应该用[pp].dbo.VW\u BEWERKINGSTRUCTUUR
中所需的列替换它。Startdag\u backwards
来自哪个表?@yvytty您想用一个真正的列连接它吗?这是因为没有具有该值的实际列,我必须计算正确的日期en,然后继续it@GarethDStartdag\u backward
来自[pp].dbo.VW\u BEWERKINGSTRUCTUUR
,我将编辑我的帖子并添加一些别名来说明这一点
SELECT MaakArtikel,
Bewerking,
b.Startdatum,
i.Class_06 AS Afdeling,
Minuten * 10 + ISNULL(br.Tijd,0) AS Minuten,
1 + ISNULL(br.Orders, 0) AS Aantal
FROM ( SELECT *,
StartDatum = [pp].dbo.WORKINGDAYADD('2013-06-27 00:00:00.000', 0 - Startdag_backwards)
FROM [pp].dbo.VW_BEWERKINGSTRUCTUUR b
) b
LEFT OUTER JOIN [211].dbo.Items i
ON b.MaakArtikel = i.ItemCode
LEFT OUTER JOIN [pp].dbo.VW_BEZETTING_RAW br
ON b.Startdatum = br.Start
AND i.Class_06 = br.Afdeling
WHERE MaakArtikel = 'HT 10.038';