Sql 获取连续n天缺勤员工名单

我有一张记录每天所有考勤的表格，我应该做一份报告，显示所有连续n天未上班的员工

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名为TimeAttention（Id、员工、AttendanceDate、CheckIn、CheckOut）的表

根据您上面添加的要求，这里是您可以做的事情

select Employee,FromDate=Min(AbsentDate),ToDate=Max(AbsentDate)
from(
select Employee,AbsentDate,count(*) over(partition by Employee,val) as AbsentDays,
       dense_rank() over(partition by Employee order by val) as OrderId
from
(select Employee,AttendanceDate as AbsnetDate,dateadd(d,-row_number() over(partition by Employee order by AttendanceDate),AttendanceDate) as val
from TimeAttendance 
where Status='Absent' -- assuming that if the employee didn't punch the Status will be 'Absent') t) x
where AbsentDays= n -- n is the n consecutive days
group by Employee

--这是更正

select Employee,FromDate=Min(AbsentDate),ToDate=Max(AbsentDate)
from(
    select Employee,AbsentDate,count(*) over(partition by Employee,val) as AbsentDays,
           dense_rank() over(partition by Employee order by val) as OrderId
    from
        (select Employee,AttendanceDate as AbsentDate,dateadd(d,-row_number() over(partition by Employee order by AttendanceDate),AttendanceDate) as val
        from TimeAttendance 
        where Status='Absent') as t -- assuming that if the employee didn't punch the Status will be 'Absent') t) x
)as x
where AbsentDays= n -- n is the n consecutive days
group by Employee

希望这能对你有所帮助

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关于

，他今天打了还是没有打