SQL Server CE 4.0选择连续数字字段

我回来尝试让这个工作（几年后）。它适用于SQL Server CE 4.0

下面是一些任何人都可以复制并运行的测试脚本

@关键字表将是用户输入的内容

这些将是歌曲ID的。每个节目都有歌曲ID和SongOrder栏

SongOrder
必须是连续的

要测试这一点，请更改
@Keywords
的顺序，
ShowId
将保留，并且不应保留

必须找到一个特定顺序的特定歌曲列表的节目

因此，用户正在寻找具有特定歌曲顺序的节目

在测试脚本中创建的每个表参数都会镜像实际数据库

SELECT
应该只返回1546，但它不是很好

--Test two shows, years apart
DECLARE @Shows TABLE (ID INT)

INSERT INTO @Shows (ID) VALUES (1)
INSERT INTO @Shows (ID) VALUES (1546)

--Add a few songs
DECLARE @Songs TABLE (ID INT, Name VARCHAR(256))

INSERT INTO @Songs (ID, Name) VALUES (1, 'Song 1')
INSERT INTO @Songs (ID, Name) VALUES (2, 'Song 2')
INSERT INTO @Songs (ID, Name) VALUES (3, 'Song 3')
INSERT INTO @Songs (ID, Name) VALUES (654, 'Song 4')
INSERT INTO @Songs (ID, Name) VALUES (321, 'Song 5')
INSERT INTO @Songs (ID, Name) VALUES (322, 'Song 6')

--Where the shows and songs get their reference
DECLARE @ShowSongRef TABLE (ID INT, ShowID INT, SongID INT, SongOrder INT, PRIMARY KEY (ID))

--Show 1
INSERT INTO @ShowSongRef (ID, ShowID, SongID, SongOrder) VALUES (1, 1, 1, 1)
INSERT INTO @ShowSongRef (ID, ShowID, SongID, SongOrder) VALUES (2, 1, 2, 2)
INSERT INTO @ShowSongRef (ID, ShowID, SongID, SongOrder) VALUES (3, 1, 321, 3)
INSERT INTO @ShowSongRef (ID, ShowID, SongID, SongOrder) VALUES (4, 1, 3, 4)
--Show 1546
INSERT INTO @ShowSongRef (ID, ShowID, SongID, SongOrder) VALUES (5, 1546, 3, 1)
INSERT INTO @ShowSongRef (ID, ShowID, SongID, SongOrder) VALUES (6, 1546, 1, 2)
INSERT INTO @ShowSongRef (ID, ShowID, SongID, SongOrder) VALUES (7, 1546, 654, 3)
INSERT INTO @ShowSongRef (ID, ShowID, SongID, SongOrder) VALUES (8, 1546, 321, 4)
INSERT INTO @ShowSongRef (ID, ShowID, SongID, SongOrder) VALUES (9, 1546, 322, 5)

--The song order we are looking for
--Doesn't matter where in the show the order occurs
DECLARE @Keyword TABLE (ID INT)
INSERT INTO @Keyword (ID) VALUES ('654')
INSERT INTO @Keyword (ID) VALUES ('321')
INSERT INTO @Keyword (ID) VALUES ('322')

--This should only return 1546
SELECT DISTINCT sh.ID AS ShowID--, s.Name 
FROM @Songs s
INNER JOIN @ShowSongRef ref ON ref.SongID = s.ID

--Comment out this join or remove the +1 and it works but in any order
INNER JOIN @ShowSongRef ref2 ON ref2.SongID = s.ID
        AND ref2.SongOrder = ref.SongOrder + 1 --remove the +1 and it works but are they in order? Not always
        AND ref2.ShowID = ref.ShowID

INNER JOIN @Shows sh ON sh.ID = ref.ShowID
WHERE ref.SongID IN (SELECT ID FROM @Keyword)

GROUP BY sh.ID
HAVING COUNT(sh.ID) = (SELECT COUNT(ID) FROM @Keyword)
--ORDER BY ref2.SongOrder

--Couldn't get this to work either
--SELECT 
--  ShowID
--FROM
--  @ShowSongRef m
--CROSS JOIN
--   (SELECT COUNT(ID) AS consec FROM @Keyword) x
--WHERE 
--  EXISTS
--     (SELECT 1 FROM @ShowSongRef ref
--          INNER JOIN @Shows sh ON sh.ID = ref.ShowID
--          WHERE ref.SongID IN (SELECT ID FROM @Keyword)
--          AND ref.SongOrder = m.SongOrder - x.consec + 1
--          )

也许：

SELECT TOP (1) WITH TIES
  showsong.ShowID, Showsong.SongId, showsong.SongOrder, song.*
FROM   @Shows       AS show
JOIN   @ShowSongRef AS showsong ON show.ID         = showsong.ShowID
JOIN   @Songs       AS song     ON showsong.SongID = song.ID
JOIN   @Keyword     AS kw       ON song.ID         = kw.ID
ORDER BY -COUNT(*) OVER (PARTITION BY showsong.ShowID);

或者，如果您不能在…

上使用窗口聚合函数（例如，

COUNT（*），则：

WITH correctId AS 
(
  SELECT TOP (1) ShowID
  FROM
  (
    SELECT showsong.ShowID, ttl = COUNT(*)
    FROM   @Shows       AS show
    JOIN   @ShowSongRef AS showsong ON show.ID         = showsong.ShowID
    JOIN   @Songs       AS song     ON showsong.SongID = song.ID
    JOIN   @Keyword     AS kw       ON song.ID         = kw.ID
    GROUP BY showsong.ShowID
  ) AS x
  ORDER BY -ttl
)
SELECT     
  showsong.ShowID, Showsong.SongId, showsong.SongOrder, song.*
FROM       @Shows       AS show
JOIN       @ShowSongRef AS showsong ON show.ID         = showsong.ShowID
JOIN       @Songs       AS song     ON showsong.SongID = song.ID
JOIN       @Keyword     AS kw       ON song.ID         = kw.ID
CROSS JOIN correctId
WHERE      showsong.ShowID = (SELECT showId FROM correctId);

原件：

也许是这样的：

SELECT TOP (1) WITH TIES *,
  -- if this number does not chnage then the song order is consecutive
  Songordercheck = showsong.songorder - 
                   ROW_NUMBER() OVER (PARTITION BY show.ID ORDER BY showsong.songorder)
FROM   @Shows       AS show
JOIN   @ShowSongRef AS showsong ON show.ID         = showsong.ShowID
JOIN   @Songs       AS song     ON showsong.SongID = song.ID
JOIN   @Keyword     AS kw       ON song.ID         = kw.ID
ORDER BY -COUNT(*) OVER (PARTITION BY show.ID)

如果我没有使用SQLCe，那么我就不会有这个问题。SQLCe不支持ROW_NUMBER（），我只是编辑了我的答案…如果有帮助，请告诉我