Sql 如何列出标签中的所有条目

有一行

“/home/pc/test”

，
以及标签中的单词

'[/alseko][/logs][/archive]

如何达到预期的效果=

我的代码，我正在尝试查找：

select '[' || '/home/pc/test' ||
       ltrim(substr('[/alseko][/logs][/archive]',
              instr('[/alseko][/logs][/archive]', '['),
              instr('[/alseko][/logs][/archive]', ']')),'[')
from dual

---

您可以使用

REGEXP\u SUBSTR

进行拆分，并使用

listag

组合路径

Oracle 11g R2架构设置：

CREATE TABLE t
    ("LINE" varchar2(13), "TAGS" varchar2(31))
;

INSERT ALL 
    INTO t ("LINE", "TAGS")
         VALUES ('/home/pc/test', '[/ alseko] [/ logs] [/ archive]')
SELECT * FROM dual
;

SELECT '[' || LISTAGG(paths, '][') WITHIN
GROUP (
        ORDER BY NULL
        ) || ']' as all_paths
FROM (
    SELECT line || '/' || REGEXP_SUBSTR(tags, '\[/ (.+?)\]', 1, LEVEL, NULL, 1) AS paths
    FROM t connect BY LEVEL <= REGEXP_COUNT(tags, '\[/ (.+?)\]')
    ) s

|                                                         ALL_PATHS |
|-------------------------------------------------------------------|
| [/home/pc/test/alseko][/home/pc/test/archive][/home/pc/test/logs] |

查询1：

CREATE TABLE t
    ("LINE" varchar2(13), "TAGS" varchar2(31))
;

INSERT ALL 
    INTO t ("LINE", "TAGS")
         VALUES ('/home/pc/test', '[/ alseko] [/ logs] [/ archive]')
SELECT * FROM dual
;

SELECT '[' || LISTAGG(paths, '][') WITHIN
GROUP (
        ORDER BY NULL
        ) || ']' as all_paths
FROM (
    SELECT line || '/' || REGEXP_SUBSTR(tags, '\[/ (.+?)\]', 1, LEVEL, NULL, 1) AS paths
    FROM t connect BY LEVEL <= REGEXP_COUNT(tags, '\[/ (.+?)\]')
    ) s

|                                                         ALL_PATHS |
|-------------------------------------------------------------------|
| [/home/pc/test/alseko][/home/pc/test/archive][/home/pc/test/logs] |

---

您可以使用

REGEXP\u SUBSTR

进行拆分，并使用

listag

组合路径

Oracle 11g R2架构设置：

CREATE TABLE t
    ("LINE" varchar2(13), "TAGS" varchar2(31))
;

INSERT ALL 
    INTO t ("LINE", "TAGS")
         VALUES ('/home/pc/test', '[/ alseko] [/ logs] [/ archive]')
SELECT * FROM dual
;

SELECT '[' || LISTAGG(paths, '][') WITHIN
GROUP (
        ORDER BY NULL
        ) || ']' as all_paths
FROM (
    SELECT line || '/' || REGEXP_SUBSTR(tags, '\[/ (.+?)\]', 1, LEVEL, NULL, 1) AS paths
    FROM t connect BY LEVEL <= REGEXP_COUNT(tags, '\[/ (.+?)\]')
    ) s

|                                                         ALL_PATHS |
|-------------------------------------------------------------------|
| [/home/pc/test/alseko][/home/pc/test/archive][/home/pc/test/logs] |

查询1：

CREATE TABLE t
    ("LINE" varchar2(13), "TAGS" varchar2(31))
;

INSERT ALL 
    INTO t ("LINE", "TAGS")
         VALUES ('/home/pc/test', '[/ alseko] [/ logs] [/ archive]')
SELECT * FROM dual
;

SELECT '[' || LISTAGG(paths, '][') WITHIN
GROUP (
        ORDER BY NULL
        ) || ']' as all_paths
FROM (
    SELECT line || '/' || REGEXP_SUBSTR(tags, '\[/ (.+?)\]', 1, LEVEL, NULL, 1) AS paths
    FROM t connect BY LEVEL <= REGEXP_COUNT(tags, '\[/ (.+?)\]')
    ) s

|                                                         ALL_PATHS |
|-------------------------------------------------------------------|
| [/home/pc/test/alseko][/home/pc/test/archive][/home/pc/test/logs] |