如何在SQL中实现这一点？

如果我有一个名为“分数”的表格，如下所示：

PLAYER DATE     SCORE
joe    3/1/13   4 
joe    3/3/13   5 
joe    3/6/13   3 
dave   3/3/13   6
dave   3/5/13   8
dave   3/7/13   7

PLAYER  LATEST_SCORE
john    3
dave    7

如何查询每位球员的最新分数？要生成这样的结果集，请执行以下操作：

PLAYER DATE     SCORE
joe    3/1/13   4 
joe    3/3/13   5 
joe    3/6/13   3 
dave   3/3/13   6
dave   3/5/13   8
dave   3/7/13   7

PLAYER  LATEST_SCORE
john    3
dave    7

---

这可以通过

行编号

实现：

SELECT Player, Date, Score
FROM
(
    SELECT Player, Date, Score, Rn = ROW_NUMBER() OVER (PARTITION BY Player ORDER BY Date DESC)
    FROM Games
) g
WHERE rn = 1

---

以下SQL在给定用户名在给定日期只能有一个条目的情况下工作

CREATE TABLE #t1 (
    player varchar(max),
    dated datetime,
    score int
)

insert into #t1 values ('joe', '2013-03-01', 4)
insert into #t1 values ('joe', '2013-03-03', 5)
insert into #t1 values ('joe', '2013-03-06', 3)

insert into #t1 values ('dave', '2013-03-03', 6)
insert into #t1 values ('dave', '2013-03-05', 8)
insert into #t1 values ('dave', '2013-03-07', 7)

SELECT  player, score
from    #t1 AS t1
WHERE   dated = (SELECT MAX(t2.DATED) FROM #t1 AS t2 WHERE t1.player = t2.player)

DROP TABLE #t1

---

将我的代码中的字段和表替换为您的

;WITH da_CTE AS (
    SELECT
        ROW_NUMBER() OVER ( PARTITION BY da_player ORDER BY da_date DESC ) AS 'RowNumber',
    da_player,
    da_date,
    da_score
   FROM #s
)

SELECT
    da_player,
    da_score
FROM da_CTE
WHERE RowNumber =1
ORDER BY da_player

---

请展示您的工作。我的建议是查看窗口函数，如

row\u number（）

，或聚合函数，如

max（）

。非常简单的解决方案，非常好！