SQL调度系统

我想创建一个考试计划系统。现在，我的目标是避免用户在SQLServer2008中为同一房间插入冲突的时间表。 例如：

对于202房间，有一个

02/27/2017 4:00pm - 5:00pm

那么，如果房间202的用户输入为

02/27/2017 3:50pm - 5:10pm

显然，这是冲突

如果我要使用between，显然它对给定的示例输入不起作用

请帮忙。

---

谢谢

就像尼克说的，之间的正是你所需要的。在这种情况下，结合

存在

或

不存在

，您将能够避免计划冲突。 只有当同一房间（同一天）的日程表中没有条目，且开始或结束时间介于新的时间段（表示冲突）之间时，才能执行插入

看看这个例子：


MS SQL Server 2008架构设置：

CREATE TABLE schedule
    ([room] int, [date] date, [start] time, [finish] time)
;

INSERT INTO schedule
    ([room], [date], [start], [finish])
SELECT  202, '2017-02-26', '16:00', '17:00'
WHERE NOT EXISTS (SELECT * 
                  FROM schedule 
                  WHERE room = '202' AND date = '2017-02-26' AND 
                   (start BETWEEN '16:00' AND '17:00'
                    OR finish BETWEEN '16:00' AND '17:00'))
;

INSERT INTO schedule
    ([room], [date], [start], [finish])
SELECT  202, '2017-02-26', '15:50', '17:10'
WHERE NOT EXISTS (SELECT * 
                  FROM schedule 
                  WHERE room = '202' AND date = '2017-02-26' AND 
                   (start BETWEEN '15:50' AND '17:10'
                    OR finish BETWEEN '15:50' AND '17:10'))
;

INSERT INTO schedule
    ([room], [date], [start], [finish])
SELECT  202, '2017-02-26', '15:00', '15:59'
WHERE NOT EXISTS (SELECT * 
                  FROM schedule 
                  WHERE room = '202' AND date = '2017-02-26' AND
                   (start BETWEEN '15:00' AND '15:59'
                    OR finish BETWEEN '15:00' AND '15:59'))
;

SELECT  *
FROM schedule

| room |       date |            start |           finish |
|------|------------|------------------|------------------|
|  202 | 2017-02-26 | 16:00:00.0000000 | 17:00:00.0000000 |
|  202 | 2017-02-26 | 15:00:00.0000000 | 15:59:00.0000000 |

查询1：

CREATE TABLE schedule
    ([room] int, [date] date, [start] time, [finish] time)
;

INSERT INTO schedule
    ([room], [date], [start], [finish])
SELECT  202, '2017-02-26', '16:00', '17:00'
WHERE NOT EXISTS (SELECT * 
                  FROM schedule 
                  WHERE room = '202' AND date = '2017-02-26' AND 
                   (start BETWEEN '16:00' AND '17:00'
                    OR finish BETWEEN '16:00' AND '17:00'))
;

INSERT INTO schedule
    ([room], [date], [start], [finish])
SELECT  202, '2017-02-26', '15:50', '17:10'
WHERE NOT EXISTS (SELECT * 
                  FROM schedule 
                  WHERE room = '202' AND date = '2017-02-26' AND 
                   (start BETWEEN '15:50' AND '17:10'
                    OR finish BETWEEN '15:50' AND '17:10'))
;

INSERT INTO schedule
    ([room], [date], [start], [finish])
SELECT  202, '2017-02-26', '15:00', '15:59'
WHERE NOT EXISTS (SELECT * 
                  FROM schedule 
                  WHERE room = '202' AND date = '2017-02-26' AND
                   (start BETWEEN '15:00' AND '15:59'
                    OR finish BETWEEN '15:00' AND '15:59'))
;

SELECT  *
FROM schedule

| room |       date |            start |           finish |
|------|------------|------------------|------------------|
|  202 | 2017-02-26 | 16:00:00.0000000 | 17:00:00.0000000 |
|  202 | 2017-02-26 | 15:00:00.0000000 | 15:59:00.0000000 |

：

CREATE TABLE schedule
    ([room] int, [date] date, [start] time, [finish] time)
;

INSERT INTO schedule
    ([room], [date], [start], [finish])
SELECT  202, '2017-02-26', '16:00', '17:00'
WHERE NOT EXISTS (SELECT * 
                  FROM schedule 
                  WHERE room = '202' AND date = '2017-02-26' AND 
                   (start BETWEEN '16:00' AND '17:00'
                    OR finish BETWEEN '16:00' AND '17:00'))
;

INSERT INTO schedule
    ([room], [date], [start], [finish])
SELECT  202, '2017-02-26', '15:50', '17:10'
WHERE NOT EXISTS (SELECT * 
                  FROM schedule 
                  WHERE room = '202' AND date = '2017-02-26' AND 
                   (start BETWEEN '15:50' AND '17:10'
                    OR finish BETWEEN '15:50' AND '17:10'))
;

INSERT INTO schedule
    ([room], [date], [start], [finish])
SELECT  202, '2017-02-26', '15:00', '15:59'
WHERE NOT EXISTS (SELECT * 
                  FROM schedule 
                  WHERE room = '202' AND date = '2017-02-26' AND
                   (start BETWEEN '15:00' AND '15:59'
                    OR finish BETWEEN '15:00' AND '15:59'))
;

SELECT  *
FROM schedule

| room |       date |            start |           finish |
|------|------------|------------------|------------------|
|  202 | 2017-02-26 | 16:00:00.0000000 | 17:00:00.0000000 |
|  202 | 2017-02-26 | 15:00:00.0000000 | 15:59:00.0000000 |

在应用程序中，使其如下所示：

伪：

SELECT count(*)
FROM schedule 
WHERE room = '202' AND date = '2017-02-26' AND
      (start BETWEEN '15:00' AND '15:59'
       OR finish BETWEEN '15:00' AND '15:59')

if count(*) = 0 then
     INSERT INTO schedule
       ([room], [date], [start], [finish])
     SELECT  202, '2017-02-26', '15:00', '15:59'
else
    ERROR "CONFLICT WITH ANOTHER SCHEDULE"
end if

两者之间是否有效取决于您检查的内容。下午4点在3:50到5:10之间。只需确保使用的数据类型正确即可。如果您有特定于代码的问题，请发布您尝试过的代码以及您正在使用的数据库类型（即MySQL或SQL Server）