找到一种使用SQL查询满足所有条件的项目列表的方法
我正在努力做到以下几点:找到一种使用SQL查询满足所有条件的项目列表的方法,sql,sql-server,tsql,Sql,Sql Server,Tsql,我正在努力做到以下几点: select i.FirstName, i.LastName, COUNT(1) from ( select u.Id, uw.WidgetId from [DB].[dbo].[Widgets] w inner join UserWidgets uw on w.Id = uw.WidgetId inner join Users u on uw.UserId = u.Id where uw.WidgetId in ('2901731
select i.FirstName, i.LastName, COUNT(1) from (
select u.Id, uw.WidgetId from [DB].[dbo].[Widgets] w inner join
UserWidgets uw on w.Id = uw.WidgetId inner join
Users u on uw.UserId = u.Id
where uw.WidgetId in ('29017318-FD89-4952-A3A2-8405BD5C5C44',
'BDB7D25C-0794-4965-842D-E6D03A250418',
'CB4553AC-A47B-4AA6-9231-5C59C8F97655')
group by u.Id, uw.WidgetId
) a
inner join [Db2].[dbo].[Identities] i on a.Id = i.IdentityId
group by i.LastName, i.FirstName
order by i.LastName, i.FirstName
我想要的是确保“In”语句要求用户只有这3个Id。不多也不少
最好的方法是什么?试试:
select i.FirstName, i.LastName, COUNT(1) from (
select u.Id, uw.WidgetId from [DB].[dbo].[Widgets] w inner join
UserWidgets uw on w.Id = uw.WidgetId
and uw.WidgetId in ('29017318-FD89-4952-A3A2-8405BD5C5C44',
'BDB7D25C-0794-4965-842D-E6D03A250418',
'CB4553AC-A47B-4AA6-9231-5C59C8F97655')
inner join Users u on uw.UserId = u.Id
left join UserWidgets uw2 on uw2.userid = u.id
and uw2.WidgetId not in ('29017318-FD89-4952-A3A2-8405BD5C5C44',
'BDB7D25C-0794-4965-842D-E6D03A250418',
'CB4553AC-A47B-4AA6-9231-5C59C8F97655')
where uw2.widgetid is null
group by u.Id, uw.WidgetId
) a
inner join [Db2].[dbo].[Identities] i on a.Id = i.IdentityId
group by i.LastName, i.FirstName
having count(1) = 3
order by i.LastName, i.FirstName
尝试:
这应该起作用:
SELECT i.firstname,
i.lastname,
COUNT(1)
FROM (SELECT u.id,
uw.widgetid
FROM [DB].[dbo].[Widgets] w
INNER JOIN userwidgets uw
ON w.id = uw.widgetid
INNER JOIN users u
ON uw.userid = u.id
WHERE uw.widgetid IN ( '29017318-FD89-4952-A3A2-8405BD5C5C44',
'BDB7D25C-0794-4965-842D-E6D03A250418'
,
'CB4553AC-A47B-4AA6-9231-5C59C8F97655' )
AND NOT EXISTS (SELECT *
FROM [DB].[dbo].[Widgets] w2
INNER JOIN userwidgets uw2
ON w2.id = uw2.id
WHERE w2.id = w.id
AND uw2.widgetid NOT IN (
'29017318-FD89-4952-A3A2-8405BD5C5C44',
'BDB7D25C-0794-4965-842D-E6D03A250418'
,
'CB4553AC-A47B-4AA6-9231-5C59C8F97655' ))
GROUP BY u.id,
uw.widgetid) a
HAVING COUNT(DISTINCT uw.widgetid) = 3
INNER JOIN [Db2].[dbo].[Identities] i
ON a.id = i.identityid
GROUP BY i.lastname,
i.firstname
ORDER BY i.lastname,
i.firstname
这应该起作用:
SELECT i.firstname,
i.lastname,
COUNT(1)
FROM (SELECT u.id,
uw.widgetid
FROM [DB].[dbo].[Widgets] w
INNER JOIN userwidgets uw
ON w.id = uw.widgetid
INNER JOIN users u
ON uw.userid = u.id
WHERE uw.widgetid IN ( '29017318-FD89-4952-A3A2-8405BD5C5C44',
'BDB7D25C-0794-4965-842D-E6D03A250418'
,
'CB4553AC-A47B-4AA6-9231-5C59C8F97655' )
AND NOT EXISTS (SELECT *
FROM [DB].[dbo].[Widgets] w2
INNER JOIN userwidgets uw2
ON w2.id = uw2.id
WHERE w2.id = w.id
AND uw2.widgetid NOT IN (
'29017318-FD89-4952-A3A2-8405BD5C5C44',
'BDB7D25C-0794-4965-842D-E6D03A250418'
,
'CB4553AC-A47B-4AA6-9231-5C59C8F97655' ))
GROUP BY u.id,
uw.widgetid) a
HAVING COUNT(DISTINCT uw.widgetid) = 3
INNER JOIN [Db2].[dbo].[Identities] i
ON a.id = i.identityid
GROUP BY i.lastname,
i.firstname
ORDER BY i.lastname,
i.firstname
我在查询中添加了'AND count(WidgetId)=3',我相信这样行吗
我在查询中添加了'AND count(WidgetId)=3',我相信这会起作用?一个问题:他们必须拥有所有三个id吗?要理解这个问题,用户必须有三个小部件,并且这三个小部件必须在in子句中列出小部件id,正确吗?您需要的操作员是“关系部门”,例如,一个问题:他们必须拥有所有三个id吗?要理解这个问题,用户必须恰好拥有三个小部件,并且这三个小部件必须在in子句中列出小部件id,正确吗?您需要的运算符是“关系分割”,例如,除非我周五下午喝啤酒的大脑出错(可能是),否则我认为您的查询将返回带有一个、两个或三个GUID的项。除非我周五下午喝啤酒的大脑出错(可能是),否则我认为您的查询将返回带有一个GUID的项,两个或三个guid。向最内部的查询添加
having count(distinct uw.widgetid)=3
将确保它具有所有三个id。您将它放在了错误的位置。它需要使用GROUP BY u.id,uw.widgetid
,但您已将其放入exists
查询中。将having count(distinct uw.widgetid)=3添加到最里面的查询将确保它具有所有三个id。您将它放在了错误的位置。它需要使用GROUP BY u.id,uw.widgetid
,但您已将其放入exists
查询中。您不能在where
子句中使用聚合语句,也不能检查用户是否有任何其他id。您是对的Allan。在group by子句之后应该有count(uw.WidgetId)=3。您不能在where
子句中使用聚合语句,并且您没有检查用户是否有任何其他ID。您是对的Allan。在GROUPBY子句之后,我应该有count(uw.WidgetId)=3。