Sql Where子句关于导致错误的视图的标准
我有一个视图,它将分隔列表。例如,如果下表包含以下两列:Sql Where子句关于导致错误的视图的标准,sql,sql-server,tsql,view,Sql,Sql Server,Tsql,View,我有一个视图,它将分隔列表。例如,如果下表包含以下两列: ABC, A;B;C 假设名称为TestView,您将得到以下结果: Label Source -------------- ABC A ABC B ABC C 代码从这里派生: 当我试图在视图的where子句中添加一个条件时,我得到了一个错误。传递给LEFT或SUBSTRING函数的长度参数无效。因此,任何类似于从TestView中选择*,其中Source='A'都会导致该错误 以下是视图中的代码: CREATE
ABC, A;B;C
假设名称为TestView,您将得到以下结果:
Label Source
--------------
ABC A
ABC B
ABC C
代码从这里派生:
当我试图在视图的where子句中添加一个条件时,我得到了一个错误。传递给LEFT或SUBSTRING函数的长度参数无效。因此,任何类似于从TestView中选择*,其中Source='A'都会导致该错误
以下是视图中的代码:
CREATE VIEW [dbo].[TestView]
AS
WITH L0 AS (SELECT 1 AS c
UNION ALL
SELECT 1),
L1 AS (SELECT 1 AS c
FROM L0 AS A,
L0 AS B),
L2 AS (SELECT 1 AS c
FROM L1 AS A,
L1 AS B),
L3 AS (SELECT 1 AS c
FROM L2 AS A,
L2 AS B),
--counts up to 256
Numbers AS (SELECT ROW_NUMBER() OVER (ORDER BY c) AS n
FROM L3)
SELECT Label,
LTRIM(RTRIM(SUBSTRING(valueTable.Sources, nums.n, charindex(N';', valueTable.Sources + N';', nums.n) - nums.n))) AS Source
FROM Numbers AS nums
JOIN dbo.SourceTable AS valueTable ON nums.n <= CONVERT(int, LEN(valueTable.Sources))
AND SUBSTRING(N';' + valueTable.Sources, n, 1) = N';'
无效的长度参数通常意味着将负值传递给子字符串函数 找出每一条记录的结果: charindexN';',valueTable.Sources+N';',nums.n-nums.n
我敢打赌charindex返回的是一个0,表示它找不到该值,并且nums.n大于0。该链接提供了指向另一篇文章的链接,该文章提供了一个性能相当好的拆分器功能 你可以试着用这个来代替
CREATE FUNCTION dbo.DelimitedSplit8K
--===== Define I/O parameters
(@pString VARCHAR(8000), @pDelimiter CHAR(1))
RETURNS TABLE WITH SCHEMABINDING AS
RETURN
--===== "Inline" CTE Driven "Tally Table" produces values from 0 up to 10,000...
-- enough to cover VARCHAR(8000)
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
), --10E+1 or 10 rows
E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
cteTally(N) AS (--==== This provides the "zero base" and limits the number of rows right up front
-- for both a performance gain and prevention of accidental "overruns"
SELECT 0 UNION ALL
SELECT TOP (DATALENGTH(ISNULL(@pString,1))) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
),
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter)
SELECT t.N+1
FROM cteTally t
WHERE (SUBSTRING(@pString,t.N,1) = @pDelimiter OR t.N = 0)
)
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found.
SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY s.N1),
Item = SUBSTRING(@pString,s.N1,ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0)-s.N1,8000))
FROM cteStart s
;
那么这将是一个
with rawData (Label,rawString) as (select 'ABC','A;B;C')
select Label,Item From rawData
Cross Apply DelimitedSplit8K(rawData.rawString, ';')
WHERE Item = 'A'
主表中有一个条目不包含值。谢谢你帮我找到了正确的线索。我会回去报告的。这篇文章的长度有些问题。但是我仍然不明白为什么它可以生成视图,但是它在where子句中失败了。但是,当我运行您发布的测试用例时,我在“.”附近得到了错误语法。好的,我已经解决了。兼容性级别需要从80提高到90。