（CTE）递归SQL查询

我对一些与递归查询相关的问题感到困惑。
我正在使用SQL SERVER 2012
我的斯内里奥， 位置是分层定义的， 每个地点都有自己的资产。
我的位置像一张桌子

Id  | Name | ParentLocationId
----+------+-----------------  
1   | L1   | NULL  
2   | L2   | 1  
3   | L3   | 1  
4   | L4   | 1  
5   | L5   | 1  
6   | L6   | 4  
7   | L7   | 4  
8   | L8   | 4  
9   | L9   | 2  
10  | L10  | 2  
11  | L11  | 6  
12  | L12  | 6  
13  | L13  | 6  

    Id | AssetNo | Description | CurrentLocationId
-------+---------+-------------+------------------
    1  | AN001   |  ADesc      | 1  
    2  | AN002   | BDesc       | 1  

我的资产表像

Id  | Name | ParentLocationId
----+------+-----------------  
1   | L1   | NULL  
2   | L2   | 1  
3   | L3   | 1  
4   | L4   | 1  
5   | L5   | 1  
6   | L6   | 4  
7   | L7   | 4  
8   | L8   | 4  
9   | L9   | 2  
10  | L10  | 2  
11  | L11  | 6  
12  | L12  | 6  
13  | L13  | 6  

    Id | AssetNo | Description | CurrentLocationId
-------+---------+-------------+------------------
    1  | AN001   |  ADesc      | 1  
    2  | AN002   | BDesc       | 1  

L1有1，L2有2，L3有0，L4有3，L5有5，L6有5，L7有1， L8有0个，L9有3个，L10有2个，L11有5个，L12有3个，L13有6个资产

我的问题是，如何计算所选位置的总数量 1级资产盘点

比如,；所选位置ID=1（L1） 样本输出为

    Id | Name | Qty 
-------+------+----- 
    2  | L2   | 7  
    3  | L3   | 0  
    4  | L4   | 23  
    5  | L5   | 5  

另一个例子；所选位置ID=4（L4）

我试着写了一个问题

WITH recursiveTable
    AS (SELECT *
         FROM   location l
         WHERE  ParentLocationId = 1
         UNION ALL
         SELECT l.*
         FROM   location l
                INNER JOIN recursiveTable r
                        ON r.Id = l.ParentLocationId),
     allLocations
     AS (SELECT *
         FROM   recursiveTable
         UNION
         SELECT *
         FROM   Location
         WHERE  Id = 0),
     resultset 
     AS (SELECT r.NAME AS LocationName,
                a.*
         FROM   allLocations r
         INNER JOIN Asset a ON a.CurrentLocationId = r.Id
         WHERE  r.DataStatus = 1)

select CurrentLocationId
       ,min(LocationName) as LocationName
       ,count(Id) as NumberOfAsset
from resultset
group by CurrentLocationId

附加的

Create Table Location
    (
      Id int,
      Name nvarchar(100),
      Description nvarchar(250),
      ParentLocationId int,
      DataStatus int
    )

    Create Table Asset
    (
      Id int,
      AssetNo nvarchar(50),
      Description nvarchar(250),
      CurrentLocationId int,
      DataStatus int
    )

    Insert Into Location Values(1,'L1','LDesc1',NULL,1)
    Insert Into Location Values(2,'L2','LDesc2',1,1)
    Insert Into Location Values(3,'L3','LDesc3',1,1)
    Insert Into Location Values(4,'L4','LDesc4',1,1)
    Insert Into Location Values(5,'L5','LDesc5',1,1)
    Insert Into Location Values(6,'L6','LDesc6',4,1)
    Insert Into Location Values(7,'L7','LDesc7',4,1)
    Insert Into Location Values(8,'L8','LDesc8',4,1)
    Insert Into Location Values(9,'L9','LDesc9',2,1)
    Insert Into Location Values(10,'L10','LDesc10',2,1)
    Insert Into Location Values(11,'L11','LDesc11',6,1)
    Insert Into Location Values(12,'L12','LDesc12',6,1)
    Insert Into Location Values(13,'L13','LDesc13',6,1)

    Insert Into Asset Values (1,'FDB-001','Desc1',1,1)
    Insert Into Asset Values (2,'FDB-002','Desc2',2,1)
    Insert Into Asset Values (3,'FDB-003','Desc3',2,1)
    Insert Into Asset Values (4,'FDB-004','Desc4',4,1)
    Insert Into Asset Values (5,'FDB-005','Desc5',4,1)
    Insert Into Asset Values (6,'FDB-006','Desc6',4,1)
    Insert Into Asset Values (7,'FDB-007','Desc7',5,1)
    Insert Into Asset Values (8,'FDB-008','Desc8',5,1)
    Insert Into Asset Values (9,'FDB-009','Desc9',5,1)
    Insert Into Asset Values (10,'FDB-010','Desc10',5,1)
    Insert Into Asset Values (11,'FDB-011','Desc11',5,1)
    Insert Into Asset Values (12,'FDB-012','Desc12',6,1)
    Insert Into Asset Values (13,'FDB-013','Desc13',6,1)
    Insert Into Asset Values (14,'FDB-014','Desc14',6,1)
    Insert Into Asset Values (15,'FDB-015','Desc15',6,1)
    Insert Into Asset Values (16,'FDB-016','Desc16',6,1)
    Insert Into Asset Values (17,'FDB-017','Desc17',7,1)
    Insert Into Asset Values (18,'FDB-018','Desc18',9,1)
    Insert Into Asset Values (19,'FDB-019','Desc19',9,1)
    Insert Into Asset Values (20,'FDB-020','Desc20',9,1)
    Insert Into Asset Values (21,'FDB-021','Desc21',10,1)
    Insert Into Asset Values (22,'FDB-022','Desc22',10,1)
    Insert Into Asset Values (23,'FDB-023','Desc23',11,1)
    Insert Into Asset Values (24,'FDB-024','Desc24',11,1)
    Insert Into Asset Values (25,'FDB-025','Desc25',11,1)
    Insert Into Asset Values (26,'FDB-026','Desc26',11,1)
    Insert Into Asset Values (27,'FDB-027','Desc27',11,1)
    Insert Into Asset Values (28,'FDB-028','Desc28',12,1)
    Insert Into Asset Values (29,'FDB-029','Desc29',12,1)
    Insert Into Asset Values (30,'FDB-030','Desc30',12,1)
    Insert Into Asset Values (31,'FDB-031','Desc31',13,1)
    Insert Into Asset Values (32,'FDB-032','Desc32',13,1)
    Insert Into Asset Values (33,'FDB-033','Desc33',13,1)
    Insert Into Asset Values (34,'FDB-034','Desc34',13,1)
    Insert Into Asset Values (35,'FDB-035','Desc35',13,1)
    Insert Into Asset Values (36,'FDB-036','Desc36',13,1)

---

致以最诚挚的问候，

我们可以应用<代码>级别和<代码>路径来尝试获取您的子项计数，但仅显示第一级子项。最后，我们按照路径对资产计数进行分组，路径是第一级子级的ID。然后仅选择末尾的第一个标高

DECLARE @LocationID INT = 1;

WITH recursiveCTE AS
(
    SELECT 
        *,
        1 AS [Level],
        Id [Path]
    FROM 
        location l
    WHERE 
        l.ParentLocationId = @LocationID
    UNION ALL 
    SELECT 
        l.*,
        [Level] + 1,
        [Path]
    FROM 
        location l
        JOIN recursiveCTE r ON l.ParentLocationId = r.Id
),
countCte AS (
    SELECT 
        [Path] Id,
        COUNT(a.AssetNo) Qty
    FROM recursiveCTE c
    JOIN Asset a ON c.Id = a.CurrentLocationId 
    GROUP BY [Path]
)

SELECT  r.Id,
        r.[Name], 
        COALESCE(c.Qty,0) Qty 
FROM    recursiveCTE r
        LEFT JOIN countCte c ON r.Id = c.Id
WHERE   r.[Level] = 1;

---

请阅读，我们需要样本数据并希望输出更快地找到答案，否则我们将浪费时间猜测您需要什么。你也可以用数据创建你的模式。谢谢你的建议。Juan，我将尝试用数据创建我的模式。你编写的查询结果有什么问题？@TabAlleman我的目标是计算所选位置的1级downOk中的资产，这与你当前查询生成的结果有什么不同？您的帖子没有显示您当前查询结果的示例。感谢您的帮助@JamieD77，也感谢您的解决方案。正是我想要的。我像往常一样仔细考虑了这件事。。不需要在第一次cte中获得复杂的路径。。只需获取ID:）