Sql 用相同的ID连接不同的数据

我需要编写SQL查询以将数据迁移到Excel文件中，我可以使用ORA_Excel从其他表中传输数据，但我无法对该特定部分执行相同的操作，因为它需要我将数据添加到此格式中。所以我计划创建一个新表并从新表调用它。我目前正在使用Oracle 10g。下面是我的表格示例

学生用书记录（---表名--）

现在，我正在尝试创建一个表，其中包含基于类似BOOK_ID的连接数据，并按日期对BOOK_描述中的信息进行排序

库\书\记录（---表名--）

---

请帮忙！！！提前谢谢你。

像这样的东西可能有用。当然，没有办法将

图书id

在其列中精确对齐（也许您可以在报告软件中至少做这么多）。我也跟着你的建议，使用了今年的两位数，尽管这是一个非常糟糕的做法，最好避免。既然这不是你问题的主题，我就不提了

在下面的查询中，首先我创建了一个“分解子查询”（顶部带有子句的

），用于测试目的。在你的工作中你不需要它；您只需要从注释行下方开始的查询。使用实际的表名和列名

with
     student_book ( book_id, checked_by, date_of_loan, hours_of_loan, comments, student )
     as (
       select 1, 'Mr.Alex', to_date('1/1/17', 'mm/dd/rr'), 1  , 'Its a good read', 'Bob'
         from dual union all
       select 2, 'Miss Li', to_date('1/2/16', 'mm/dd/rr'), 0.5, 'Its alright'    , 'Tom'
         from dual union all
       select 2, 'Miss Li', to_date('1/1/17', 'mm/dd/rr'), 3  , 'Its a bad book' , 'Tim'
         from dual union all
       select 1, 'Mr.Alex', to_date('3/1/15', 'mm/dd/rr'), 2  , 'Its boring'     , 'Jane'
         from dual union all
       select 1, 'Mr.Alex', to_date('4/1/12', 'mm/dd/rr'), 5  , 'Fun to read'    , 'Sally'
         from dual
     )
--  end of test data; SQL query begins BELOW THIS LINE.
select book_id,
       'Total Hours of Loan: ' || to_char(sum(hours_of_loan)) || chr(10) || 
       lpad('-', 30, '-')      || chr(10) ||
       listagg(descr, chr(10)  || lpad('-', 30, '-') || chr(10))
               within group (order by date_of_loan)  as book_description
from   (
         select book_id, date_of_loan, hours_of_loan,
                'Written by: '      || checked_by                          || chr(10) ||
                'Date of Loan : '   || to_char(date_of_loan, 'mm/dd/yy')   || chr(10) ||
                'Hour(s) of Loan: ' || to_char(hours_of_loan)              || chr(10) ||
                'Comments: '        || comments                            || chr(10) ||
                'Student: '         || student      as descr
         from   student_book
       )
group by book_id
order by book_id
;

输出：

BOOK_ID BOOK_DESCRIPTION
------- --------------------------------
      1 Total Hours of Loan: 8
        ------------------------------
        Written by: Mr.Alex
        Date of Loan : 04/01/12
        Hour(s) of Loan: 5
        Comments: Fun to read
        Student: Sally
        ------------------------------
        Written by: Mr.Alex
        Date of Loan : 03/01/15
        Hour(s) of Loan: 2
        Comments: Its boring
        Student: Jane
        ------------------------------
        Written by: Mr.Alex
        Date of Loan : 01/01/17
        Hour(s) of Loan: 1
        Comments: Its a good read
        Student: Bob

      2 Total Hours of Loan: 3.5
        ------------------------------
        Written by: Miss Li
        Date of Loan : 01/02/16
        Hour(s) of Loan: .5
        Comments: Its alright
        Student: Tom
        ------------------------------
        Written by: Miss Li
        Date of Loan : 01/01/17
        Hour(s) of Loan: 3
        Comments: Its a bad book
        Student: Tim

编辑：对于11之前的Oracle版本，
listag（）
将不起作用
xmlagg（）
早就存在了（我相信）。下面的修改应该有效。（它在每本书描述的底部都会产生一条额外的“虚线”，如果需要，可以删除它——我不介意）

替换

   listagg(descr, chr(10)  || lpad('-', 30, '-') || chr(10))
           within group (order by date_of_loan)  as book_description

与

所需的输出不是SQL查询的传统输出。你应该在应用程序级别进行重新排列。
listag（）
可能会让你走到一半，但正如@Gordon所说，如果你真的想要这种格式，应该在你的应用程序代码中完成。Hello@GordonLinoff，感谢您的建议，但我需要为此作业编写SQL查询，以便将数据迁移到其他格式。嘿@TimBiegeleisen，谢谢您的帮助，我将研究Listag（），是的，我确实需要这种格式。我必须编写SQL查询并将数据迁移到Excel文件中，我可以使用ORA_EXCEL从其他表中传输数据，但我无法对这个特定部分执行相同的操作，因为它需要我将数据添加到此格式Hey@mathguy感谢您的帮助，并对延迟回复表示抱歉=D我从未想过以这种方式编写查询，但我无法使用“Listag”由于my Oracle的版本是10g，并且Listag只能在Oracle 12c、Oracle 11g第2版中使用，很抱歉在此之前没有提及。还有别的办法吗？@Laran-我会补充一些答案；我相信Oracle 10中提供了
xmlagg
。
BOOK_ID BOOK_DESCRIPTION
------- --------------------------------
      1 Total Hours of Loan: 8
        ------------------------------
        Written by: Mr.Alex
        Date of Loan : 04/01/12
        Hour(s) of Loan: 5
        Comments: Fun to read
        Student: Sally
        ------------------------------
        Written by: Mr.Alex
        Date of Loan : 03/01/15
        Hour(s) of Loan: 2
        Comments: Its boring
        Student: Jane
        ------------------------------
        Written by: Mr.Alex
        Date of Loan : 01/01/17
        Hour(s) of Loan: 1
        Comments: Its a good read
        Student: Bob

      2 Total Hours of Loan: 3.5
        ------------------------------
        Written by: Miss Li
        Date of Loan : 01/02/16
        Hour(s) of Loan: .5
        Comments: Its alright
        Student: Tom
        ------------------------------
        Written by: Miss Li
        Date of Loan : 01/01/17
        Hour(s) of Loan: 3
        Comments: Its a bad book
        Student: Tim

   listagg(descr, chr(10)  || lpad('-', 30, '-') || chr(10))
           within group (order by date_of_loan)  as book_description

xmlagg(xmlelement(x, descr, chr(10) || lpad('-', 30, '-') || chr(10)).extract('//text()')
                         order by date_of_loan)  as book_description