Sql 在Oracle 9i中拆分逗号分隔的值
在Oracle中,我有称为OrderID的列Sql 在Oracle 9i中拆分逗号分隔的值,sql,oracle,oracle9i,Sql,Oracle,Oracle9i,在Oracle中,我有称为OrderID的列 orderids 111,222,333 444,55,66 77,77 如何获得输出 Orderid 111 222 333 444 55 66 77 77 试试这个: WITH TT AS (SELECT orderid COL1 FROM orders) SELECT substr(str, instr(str, ',', 1, LEVEL) + 1, ins
orderids
111,222,333
444,55,66
77,77
如何获得输出
Orderid
111
222
333
444
55
66
77
77
试试这个:
WITH TT AS
(SELECT orderid COL1 FROM orders)
SELECT substr(str,
instr(str, ',', 1, LEVEL) + 1,
instr(str, ',', 1, LEVEL + 1) -
instr(str, ',', 1, LEVEL) - 1) COL1
FROM (SELECT rownum AS r,
','|| COL1||',' AS STR
FROM TT )
CONNECT BY PRIOR r = r
AND instr(str, ',', 1, LEVEL + 1) > 0
AND PRIOR dbms_random.STRING('p', 10) IS NOT NULL
;
见此这是一种方法:
with order_table as (
select '111,222,333' as orderids from dual
union all select '444,55,66' from dual
union all select '77,77' from dual
)
select substr(orderids, instr(orderids, ',', 1, lvl) + 1, instr(orderids, ',', 1, lvl + 1) - instr(orderids, ',', 1, lvl) - 1) orderid
from
( select ',' || orderids || ',' as orderids from order_table ),
( select level as lvl from dual connect by level <= 100 )
where lvl <= length(orderids) - length(replace(orderids, ',')) - 1;
只需删除WITH子句,并将order_表替换为实际表。这也可能对您有所帮助
with t(orderid) as
(
SELECT '111,222,333' FROM dual
UNION
SELECT '444,55,66' FROM dual
UNION
SELECT '177,77' FROM dual
)
SELECT trim(x.COLUMN_VALUE.EXTRACT('e/text()')) cols
FROM t t, TABLE (xmlsequence(XMLTYPE('<e><e>' || REPLACE(t.orderid,',','</e><e>')|| '</e></e>').EXTRACT('e/e'))) x;
这是我正在寻找的实际查询。以后,请花更多时间格式化您的问题。因为您没有格式化预期和实际输出,所以所有数字都在同一行,并且这个问题很容易引起误解。这一次我已经解决了。如果你在谷歌上搜索oracle,将字符串拆分成行,你会找到你要查找的内容,例如,Nope@Codo,正则表达式是在10g中引入的,这意味着通常的方法不起作用,这就是我没有关闭的原因。好的观点。但是它也可以用INSTR和SUBSTR来完成。是的,还有。我希望每个单词都在单独的行中
instr(','||NVL('972414AQ,972414AQ',I.CUSIP)||',', ','||I.CUSIP||',') > 0