Sql 如何从列表中删除所有重复对？

我想添加CY的所有值，其中PY值与每个PID相同

换句话说：PID 1的PY和PID 4的PY是相同的。 PID 2和PID 5的PY相同

Select
    [ID] ,a.[PY] ,a.[CY] ,a.[LAT] ,a.[LON] Into #tempa
        From MyTable as a
            INNER JOIN MyTable as b on a.PY = b.PY and a.ID <> b.ID

Select
    Convert (varchar, LAT) + ', ' + convert (varchar, LON) as 'Combined', 
    SUM(CY) as Total ,COUNT(ID) as [Count] Into #tempb
        From #tempa
            Group by Convert (varchar, LAT) + ', ' + convert (varchar, LON)
            Having COUNT(ID) < 2

Select
    SUM(Total) as [Total]
        From #tempb

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如何仅添加ID 1、4和5的CY值？

您可以非常轻松地删除第2行和第3行：

select *
from insurance i
where not exists (select 1
                  from insurance i2
                  where i2.location_pair = i.location_pair and i2.pid <> i.pid
                 );

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但是，这不会返回指定的结果。是一个数字小提琴。

您为什么想要ID 1行而不是2或3行？这是答案吗？如果没有，请编辑您的问题并将此代码放在那里，然后删除此帖子。如果是，请编辑并注明这是您问题的答案。

select min(pid), py, sum(cy), min(location_pair)
from insurance i
where not exists (select 1
                  from insurance i2
                  where i2.location_pair = i.location_pair and i2.pid <> i.pid
                 )
group by py;

Select * Into #temp2 From #temp t
Where Exists (
Select 1 From #temp t2
Where i2.PY = t.PY and t2.ID <> t.ID);
Select * Into #temp3 From #temp t
Where Not exists (
Select 1 From #Temp t2
Where t2.ID <> t.ID);

Select * From #temp2
Select * From #temp3

SELECT SUM(a.CY) as CY FROM #temp2 a
INNER JOIN #temp3 b on a.ID = b.ID